430 likes | 449 Views
Algebra 1 Notes Lesson 7-4 Elimination Using Multiplication. Mathematics Standards Number, Number Sense and Operations : Explain the effects of operations such as multiplication or division, and of computing the powers and roots on the magnitude of quantities.
E N D
Algebra 1 Notes Lesson 7-4 Elimination Using Multiplication
Mathematics Standards • Number, Number Sense and Operations: Explain the effects of operations such as multiplication or division, and of computing the powers and roots on the magnitude of quantities. • Patterns, Functions and Algebra: Add, subtract, multiply and divide monomials and polynomials. • Patterns, Functions and Algebra: Solve real-world problems that can be modeled using linear, quadratic, exponential or square root functions.
Mathematics Standards • Patterns, Functions and Algebra: Solve and interpret the meaning of 2 by 2 systems of linear equations graphically, by substitution and by elimination, with and without technology. • Patterns, Functions and Algebra: Solve real world problems that can be modeled using systems of linear equations and inequalities.
Elimination with Multiplication One more step than before
Example 1 Use elimination to solve the system of equations. 2x +y = 23 3x + 2y = 37 multiply by 2
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 keep the same
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 3x + 2y = 37
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 x = 9
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 x = 9
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 .
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 27 + 2y = 37
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 27 + 2y = 37 – 27 – 27
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 . 27 + 2y = 37 – 27 – 27 2y = 10
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 27 + 2y = 37 – 27 – 27 2y = 10 2 2
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 27 + 2y = 37 – 27 – 27 2y = 10 2 2 y = 5
Example 1 Use elimination to solve the system of equations. 2x +y = 23 multiply by 2 4x + 2y = 46 3x + 2y = 37 (–) 3x + 2y = 37 3(9) + 2y = 37 x = 9 27 + 2y = 37 – 27 – 27 (9, 5) 2y = 10 2 2 y = 5
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 3x – 5y = -23
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 3x – 5y = -23
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4 12x – 20y = -92
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4 (-)12x – 20y = -92 29y = 116 29 29 y = 4
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4(-)12x – 20y = -92 29y = 116 29 29 y = 4
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4(-)12x – 20y = -92 3x – 5(4) = -23 29y = 116 29 29 y = 4
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4(-)12x – 20y = -92 3x – 5(4) = -23 29y = 116 3x – 20 = -23 29 29 y = 4
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4 (-)12x – 20y = -92 3x – 5(4) = -23 29y = 116 3x – 20 = -23 29 29 +20 +20 y = 4 3x = -3 3 3
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4 (-)12x – 20y = -92 3x – 5(4) = -23 29y = 116 3x – 20 = -23 29 29 +20 +20 y = 4 3x = -3 3 3 x = -1
Example 2 Use elimination to solve the system of equations. 4x + 3y = 8 multiply by 3 12x + 9y = 24 3x – 5y = -23 multiply by 4 (-)12x – 20y = -92 3x – 5(4) = -23 29y = 116 3x – 20 = -23 29 29 +20 +20 y = 4 3x = -3 3 3 x = -1 (-1, 4)
Example 3 Determine the best method to solve the system of equations. Then solve the system. x + 5y = 4 3x – 7y = -10
Example 3 Three Options: Graphing – Rarely best Substitution – If variable is solved for or easily solved for Elimination – If variable has same coefficient or solving for a variable gives a fraction
Example 3 Determine the best method to solve the system of equations. Then solve the system. x + 5y = 4 3x – 7y = -10 The best method to use is substitution because the coefficient of x in the first equation is 1, which makes it easy to solve for.
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y x = 4 – 5y
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y x = 4 – 5y
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y 12 – 15y – 7y = -10 12 – 22y = -10 – 12 – 12 -22y = -22 -22 -22 y = 1
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y12 – 15y – 7y = -10 12 – 22y = -10 – 12 – 12 -22y = -22 -22 -22 y = 1
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y12 – 15y – 7y = -10 x = 4 – 5(1) 12 – 22y = -10 – 12 – 12 -22y = -22 -22 -22 y = 1
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y12 – 15y – 7y = -10 x = 4 – 5(1) 12 – 22y = -10 x = 4 – 5 – 12 – 12 -22y = -22 -22 -22 y = 1
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y12 – 15y – 7y = -10 x = 4 – 5(1) 12 – 22y = -10 x = 4 – 5 – 12 – 12 x = -1 -22y = -22 -22 -22 y = 1
Example 3 x + 5y = 4 3x – 7y = -10 – 5y – 5y 3(4 – 5y) – 7y = -10 x = 4 – 5y12 – 15y – 7y = -10 x = 4 – 5(1) 12 – 22y = -10 x = 4 – 5 – 12 – 12 x = -1 -22y = -22 (-1, 1) -22 -22 y = 1
Homework Pg. 391 14-38 evens