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Algebra 1 Lesson: Order of Operations Practice

Learn how to write expressions from word problems and evaluate them using PEMDAS. Practice with examples and exercises provided.

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Algebra 1 Lesson: Order of Operations Practice

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  1. Algebra 1 Notes:Lesson 1-2:Order of Operations

  2. Objectives • Write expressions from a story problem • Evaluate expressions using order of operations

  3. Order of Operations • Parentheses. • Exponents. • Multiplication and • Division from left to right. • 4. Addition and • Subtractions from left to right.

  4. P E M D A S

  5. Please Excuse My Dear Aunt Sally

  6. Please Parenthesis Excuse Exponents My Multiplication Dear Division Aunt Addition Sally Subtraction

  7. Example 1 2[5 + (30  6)2]

  8. Example 1 2[5 + (30  6)2]

  9. Example 1 2[5 + (30  6)2]

  10. Example 1 2[5 + (30  6)2] = 2[5 + (5)2]

  11. Example 1 2[5 + (30  6)2] = 2[5 + (5)2]

  12. Example 1 2[5 + (30  6)2] = 2[5 + (5)2]

  13. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25]

  14. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25]

  15. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25]

  16. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25] = 2[30]

  17. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25] = 2[30]

  18. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25] = 2[30]

  19. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25] = 2[30] = 60

  20. Example 1 2[5 + (30  6)2] = 2[5 + (5)2] = 2[5 + 25] = 2[30] = 60

  21. Example 2 Simplify the top first.

  22. Example 2 Next simplify the bottom.

  23. Example 2 Leave your answer as a simplified fraction – do not divide to make it a decimal.

  24. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5

  25. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c)

  26. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4 5)

  27. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5)

  28. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5)

  29. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5)

  30. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5)

  31. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5)

  32. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5)

  33. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20)

  34. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20)

  35. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20)

  36. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7

  37. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7

  38. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7

  39. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7 = 49 – 7

  40. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7 = 49 – 7

  41. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7 = 49 – 7

  42. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7 = 49 – 7 = 42

  43. Example 3 Evaluate a2 – (b3 – 4c) if a = 7, b = 3, and c = 5 a2 – (b3 – 4c) = 72 – (33 – 4  5) = 72 – (27 – 4  5) = 72 – (27 – 20) = 72 – 7 = 49 – 7 = 42

  44. Write an expression A computer store is selling software packages on sale at 3 for $20. Individual software packages costs $9.95. Write an expression to find the cost of 5 software packages. How much would 5 software packages cost?

  45. Write an expression A computer store is selling software packages on sale at 3 for $20. Individual software packages costs $9.95. Write an expression to find the cost of 5 software packages. 20 + 2(9.95) How much would 5 software packages cost?

  46. Write an expression A computer store is selling software packages on sale at 3 for $20. Individual software packages costs $9.95. Write an expression to find the cost of 5 software packages. 20 + 2(9.95) 20 + 19.90 How much would 5 software packages cost?

  47. Write an expression A computer store is selling software packages on sale at 3 for $20. Individual software packages costs $9.95. Write an expression to find the cost of 5 software packages. 20 + 2(9.95) 39.90 20 + 19.90 How much would 5 software packages cost?

  48. Write an expression A computer store is selling software packages on sale at 3 for $20. Individual software packages costs $9.95. Write an expression to find the cost of 5 software packages. 20 + 2(9.95) 39.90 20 + 19.90 How much would 5 software packages cost? $39.90

  49. Try these on your own 1) 48 – 23  3 + 5 2) 4 [ 12 ÷ (6 – 2)]2 • 25 – 6  2 4) a2 – ( b3 – 4c) 33 – 5  3 – 2 a = 7, b = 3, c = 5 5) 2k + gh2 – j 6) 2g ( h- g) gh - j k = 12, g = 4, h = 6, j = 8

  50. Try these on your own 1) 48 – 23  3 + 5 2) 4 [ 12 ÷ (6 – 2)]2 29 36 • 25 – 6  2 4) a2 – ( b3 – 4c) 33 – 5  3 – 2 a = 7, b = 3, c = 5 5) 2k + gh2 – j 6) 2g ( h- g) gh – j k = 12, g = 4, h = 6, j = 8

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