570 likes | 2.67k Views
Ion Association. Ion pair formation. Ion Association. Ion pair formation. fully solvated. solvent-shared or solvent-separated Ion pair. c ontact ion pair. Ion pairs formed when opposite ions come close enough to be separated by a distance < r*. Bjerrum. As
E N D
Ion Association Ion pair formation
Ion Association Ion pair formation fully solvated solvent-shared or solvent-separated Ion pair contact ion pair Ion pairs formed when opposite ions come close enough to be separated by a distance < r*
Bjerrum • As • Charge of ions increases (zi): r* increases, probability of ion pair formation increases. • Temperature increases, r* decreases, probability of IP formation decreases. Kinetic energy acts against attraction. • Polarity of solvent increases (er), attraction decreases, probability of IP formation decreases
Electrostatic potential energy for inter-action between two univalent ions: Substitute r = r* For univalent electrolyte in water at 25oC, IP formation is negligible r* is only 0.358 nm. Very difficult to bring the opposite ions so close!
Transport Numbers c = 1 M c+= a M c-= b M
Let 4F be passed through the cell; t+=3t- Before electrolysis On electrolysis After electrolysis
Let 4F be passed through the cell; t+=3t- 4 Cl- -4e- 2 Cl2 4 H+ +4e- 2 H2 3 mol H+ 1 mol Cl- 3 mol H+ 1 mol Cl-
For anodic region: Cresidual = Cinitial – Creact + Ctransfer 3 = 6 – 4 + Ctransfer t- = 1 / 4 = 0.25 t+ = 3 / 4 = 0.75
measurement of transport numbers by Hittorf method The method of Hittorf is based on concentration changes in the anodic region and cathodic region in an electrolytic cell, caused by the passage of current through the electrolyte.
A solution of LiCl was electrolyzed in a Hittorf cell. After a current of 0.79 A had been passed for 2 h, the mass of LiCl in the anode compartment has decreased by 0.793 g. Calculate the transport numbers of Li+ and Cl-. If Lo(LiCl) is 115 W-1cm2mol-1, what are the molar ionic conductivities and the ionic mobilities?
2) The moving-boundary method MA, MA’ have an ion in common. The boundary, rather difference in color, refractivity, etc. is sharp. In the steady state, the two ions move with the same velocity.
When Q coulomb passes, the boundary moves x, the cross-sectional area of the tube is A: No. of mole of H+ that passed from AA’ to BB’ n=c.V=c+.A.x Charge carried by these moles: Q+=z+ F n+=z+ F c+ A x
Sample: When A = 1.05×10-5m2, c(HCl) = 10.0 mol m-3, I = 0.01 A for 200 s, x was measured to be 0.17 m. Calculate t (H+). Solution: t+ = 0.17 m× 1.05 × 10-5 m2 × 10.0 mol m-3 ×1 × 96500 C mol-1 / 0.01 A × 200 S = 0.82
Kohlrausch’s Law of Independent migration Valid only at infinite dilution!
Grotthuss Mechanism Explains the high conductivity of H+ and OH- in water
Ion Solvation Size But larger size means slower motion, the conductivity should drop?!!!! • Smaller size, • larger interaction with water molecule, • hydrate shell larger on Li+, • moving species larger, • Lower conductivity
Viscosity of the solvent Walden’s Rule L.h = constant