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AP Physics Chpts 6-9 Test

AP Physics Chpts 6-9 Test. Solutions. Question 1 ] . to find a ( a = -4.1 m/s 2 ) Newton’s 2nd Law with kinetic friction as only force In the end : - μ k = a/g = (- 4.1 m/s 2 )/(9.81 m/s 2 ). Question 2 ]. ( mechanical energy is denoted by E ) E = KE + PE =

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AP Physics Chpts 6-9 Test

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  1. AP Physics Chpts 6-9 Test Solutions

  2. Question 1 ] • to find a ( a = -4.1 m/s2 ) • Newton’s 2nd Law with kinetic friction as only force • In the end : - μk = a/g= (-4.1 m/s2)/(9.81 m/s2 )

  3. Question 2 ] • ( mechanical energy is denoted by E ) • E= KE + PE = • h is 4 feet ( 1.2 m ) if floor is chosen as reference ( the floor is the typical reference ) • Use initial velocity and convert m to kg

  4. Question 3 ] • Total Energy is always conserved, but mechanical energy is conserved as long as non-conservative forces are absent. Non-conservative forces dissipate the velocity of the salt shaker in this case and the mechanical energy is therefore dissipated somewhat. That lost kinetic energy can not be re-harnessed.

  5. Question 4 ] T • Use results from Question 1 to find fk fk

  6. Question 5 ] • Elastic Collision • + ( momentum conserved ) • + ( KE conserved )

  7. Question 5 ] • Get the equations below for both final velocities • vo is the initial velocity given in “physical picture” • where m1 is the salt shaker • where v2 is for pepper shaker

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