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Concrete Structures

Concrete Structures. Units of Measure. Concrete: Cubic Yard Steel: Lb or tons Formwork: Square feet per contact area. Types of Concrete construction. 1. Foundations 2. Columns 3. Slabs and beams. Shallow Foundation. Isolated Footing. Combined Footing. Continuous Wall Footing.

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Concrete Structures

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  1. Concrete Structures Prof Awad S. Hanna

  2. Units of Measure Concrete: Cubic Yard Steel: Lb or tons Formwork: Square feet per contact area Prof Awad S. Hanna

  3. Types of Concrete construction 1. Foundations 2. Columns 3. Slabs and beams Prof Awad S. Hanna

  4. Prof Awad S. Hanna

  5. Shallow Foundation Isolated Footing Combined Footing Continuous Wall Footing Strap Footing Raft Foundation Prof Awad S. Hanna

  6. Deep Foundation Caissons Piles Prof Awad S. Hanna

  7. Columns • Shapes • Square - Rectangle - Circular • Others • Reinforcement • Ordinary - Spiral Prof Awad S. Hanna

  8. Slabs and Beams: One-Way slabs One-Way Slab, Beam, and Girder One-Way Slab, Supported by Beams or Walls One-Way Joist Slab Prof Awad S. Hanna

  9. Slabs and Beams: Two-Way Slabs Flat Plate Waffle Slab Flat Slab Two-Way Slab Supported by Beams Prof Awad S. Hanna

  10. Estimating Issues 1. Formwork is the largest cost item that represent 40% to 60% of concrete structure cost. Distribution of costs for cast-in-place concrete slab wall: Prof Awad S. Hanna

  11. 2.Waste allowance from 2% to 10% should be added for concrete and concrete formwork. Prof Awad S. Hanna

  12. 1. Center Line Method Building size: 30’ x 40’ Calculations: 1. Length = 30’10” - 1’6” = 29’4” 2. Width = 40’10” - 1’6” = 39’4” 3. Perimeter = 29’4” + 29’4” + 39’4” +39’4” = 137”4” 4. Volume of concrete = 137.33’ x 1’ x 1.5’ = 206 ft3 30’10” 30’ 40’0” 40’10” Prof Awad S. Hanna

  13. 2. Sectional Method Calculations: 1.Length = 10.833’+40.833’ = 81.67’ 2.Width = 27.833’+27.833’ = 55.67’ 3.Perimeter = 81.67’+55.67’ = 137.34 Total Linear ft 4.Volume = 137.34’x1’x1.5’ = 206 Cubic feet 5.volume in CY = 206/27 = 7.6 Cubic Yards 30’10” 27’10” 40’10” Prof Awad S. Hanna

  14. COST OF OTHER COMPONENTS OF CONCRETE WORK 1. Reinforcement Steel 2. Forms 3. Concrete Mix 4. Finishing 5. Curing Prof Awad S. Hanna

  15. Table 1.DIMENSIONS & WEIGHT OF WELDED WIRE FABRIC Prof Awad S. Hanna

  16. Table 2SIZES & WEIGHTS OF REINFORCING BAR Prof Awad S. Hanna

  17. EXAMPLE: How many pounds of rebar are required for the concrete floor area below? 60’ 20’ 6” Concrete slab with #4 rebar 15” on center each way 40’ 30’ Prof Awad S. Hanna

  18. Step #1: Calculate the total SF of area involved. 20'0" X 30'0" = 600 SF 30'0" X 40'0" = 1 200 SF Total = 1,800 SF floor area Step #2: Calculate the pounds of rebar per SF of floor based on the unit spacing of the rebar at any point of intersection. Unit area: 15" X 15" = 1.25' X 1.25' = 1.56 SF Unit rebar length: 1.25' + 1.25' = 2.5 LF Lbs. of rebar/unit:= 2.5 LF X .668 lbs/ LF = 1.67 lbs • It is now known that there are 1. 67 lbs of rebar per 1.56 SQ FT of floor area. 1.67 / 1.56 = 1.07 lbs/SF of floor area. SO: 1.07 lbs/ SF X 1,800 SF = 1,926 lbs of #4 rebar required. Prof Awad S. Hanna

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