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Electrochemistry Lesson 4 Using Oxidation Numbers. Using Oxidation Numbers If the oxidation number of the central atom increase s going from left to right , its oxidation . Cl O 2 - Cl O 4 -. Increase is oxidation. +3. +7. oxidation. reducing agent. 4 electrons lost.
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Electrochemistry Lesson 4 Using Oxidation Numbers
Using Oxidation Numbers If the oxidation number of the central atomincreases going from left to right, its oxidation. ClO2-ClO4- Increase is oxidation +3 +7 oxidation reducing agent 4 electronslost
Using Oxidation Numbers If the oxidation number of the central atomdecreases going from left to right, its reduction. NO3- HNO2 +5 +3 decrease is reduction reduction 2 electronsgained oxidizing agent
Label the oxidizing agent and the reducing agent. +7+1+50 ReO4- + IO- IO3- + Re Reduced Oxidized Ox Agent Red Agent
Label the oxidizing agent and the reducing agent. +3+5 +5 +2 3As2O3 + 4NO3- + 7H2O + 4H+6H3AsO4 + 4NO oxidized reduced red agent ox agent
Predicting Spontaneous Reactions Using the Standard Reduction Chart Does Au3+ react with Cl-? If it does write the spontaneous reaction.
The top reaction is written forward- reduction The bottom reaction is written in reverse- oxidation (Au3+ + 3e- Au(s)) 2 (2Cl- Cl2(g) + 2e-) 3 2Au3+ + 6Cl-3Cl2(g) + 2Au(s)
Some ionsare on both sidesof the table and are oxidizing or reducing agents. For example: Fe Fe2+ Fe3+ Sn Sn2+ Sn4+ Cu Cu+ Cu2+
Check both spontaneous (Sn2+ + 2e- Sn(s)) 3 (Cr(s) Cr3+ + 3e-) 2 2Cr (s) + 3Sn2+2Cr3+ + 3Sn(s)
Can you keep HCl in a Cu container? Explain! Yes, nonspontaneous. H+ is a weaker oxidizing agent than Cu2+ and Cu+.
Spontaneous- no H+ is a stronger oxidizing agent than Zn2+
Write the spontaneous reaction. 2H+ + 2e- H2(g) Zn(s) Zn2+ + 2e- 2H+ + Zn(s) H2(g) + Zn2+
Can you keep HNO3 in a Au container? Explain! Yes, nonspontaneous. HNO3is a weaker oxidizing agent than Au3+.
Take the strongest ox agent- higher Take the strongest red agent- lower
Can you keep HNO3 in a Cu container? No, spontaneous. HNO3 is a stronger oxidizing agent than Cu2+. Write the spontaneous reaction. NO3- + 4H+ + 3e- NO(g) + 2H2O x 2 Cu(s) Cu2+ + 2e- x 3 2NO3- + 8H+ + 3Cu(s) 2NO(g) + 4H2O + 3Cu2+