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Symmetrical Components I An Introduction to Power System Fault Analysis Using Symmetrical Components. Dave Angell Idaho Power 21st Annual Hands-On Relay School. What Type of Fault?. What Type of Fault?. What Type of Fault?. What Type of Fault?. What Type of Fault?. What Type of Fault?.
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Symmetrical Components IAn Introduction to Power System Fault Analysis Using Symmetrical Components Dave Angell Idaho Power 21st Annual Hands-On Relay School
Basic Course Topics • Terminology • Phasors • Equations • Fault Analysis Examples • Calculations
Symmetrical Component Phasors • The unbalanced three phase system can be transformed into three balanced phasors. • Positive Sequence • Negative Sequence • Zero Sequence
Positive Phase Sequence • Each have the same magnitude. • Each positive sequence voltage or current quantity is displaced 120° from one another.
Positive Phase Sequence • The positive sequence quantities have a-b-c, counter clock-wise, phase rotation.
Negative Phase Sequence • Each have the same magnitude. • Each negative sequence voltage or current quantity is displaced 120° from one another.
Negative Phase Sequence • The negative sequence quantities have a-c-b, counter clock-wise, phase rotation.
Zero Phase Sequence • Each zero sequence quantity has the same magnitude. • All three phasors with no angular displacement between them, all in phase.
Symmetrical Components Equations • Each phase quantity is equal to the sum of its symmetrical phasors. • Va = Va0 + Va1+Va2 • Vb = Vb0 + Vb1 +Vb2 • Vc = Vc0 + Vc1 +Vc2 • The common form of the equations are written in a-phase terms.
The a Operator • Used to shift the a-phase terms to coincide with the b and c-phase • Shorthand to indicate 120° rotation. • Similar to the j operator of 90°.
Rotation of the a Operator • 120° counter clock-wise rotation. • A vector multiplied by 1 /120° results in the same magnitude rotated 120°.
Rotation of the a2 Operator • 240° counter clock-wise rotation. • A vector multiplied by 1 /240° results in the same magnitude rotated 240°.
B-Phase Zero Sequence • We replace the Vb sequence terms by Va sequence terms shifted by the a operator. • Vb0 = Va0
B-Phase Positive Sequence • We replace the Vb sequence terms by Va sequence terms shifted by the a operator • Vb1 = a2Va1
B-Phase Negative Sequence • We replace the Vb sequence terms by Va sequence terms shifted by the a operator • Vb2 = aVa2
C-Phase Zero Sequence • We replace the Vc sequence terms by Va sequence terms shifted by the a operator. • Vc0 = Va0
C-Phase Positive Sequence • We replace the Vc sequence terms by Va sequence terms shifted by the a operator • Vc1 = aVa1
C-Phase Negative Sequence • We replace the Vc sequence terms by Va sequence terms shifted by the a operator • Vc2 = a2Va2
What have we produced? • Va = Va0+ Va1 + Va2 • Vb = Va0 + a2Va1 + aVa2 • Vc = Va0 + aVa1 + a2Va2
Symmetrical Components Equations • Analysis • To find out of the amount of the components • Synthesis • The combining of the component elements into a single, unified entity
Symmetrical Components Synthesis Equations • Va = Va0+ Va1 + Va2 • Vb = Va0 + a2Va1 + aVa2 • Vc = Va0 + aVa1 + a2Va2
Symmetrical Components Analysis Equations • Va0 = 1/3 ( Va + Vb + Vc) • Va1= 1/3(Va + aVb + a2Vc) • Va2= 1/3 (Va + a2Vb + aVc)
Symmetrical Components Analysis Equations - 1/3 ?? • Where does the 1/3 come from? • Va1= 1/3(Va + aVb + a2Vc) • Va = Va0 + Va1 + Va2 • When balanced
Symmetrical Components Analysis Equations - 1/3 ?? • Va1= 1/3(Va + aVb + a2Vc) • Adding the phases
Symmetrical Components Analysis Equations - 1/3 ?? • Va1= 1/3(Va + aVb + a2Vc) • Adding the phases yields
Symmetrical Components Analysis Equations - 1/3 ?? • Va1= 1/3(Va + aVb + a2Vc) • Adding the phases yields 3 Va. • Divide by the 3 and now Va = Va1
Example VectorsAn Unbalanced Voltage • Va = 13.4 /0° • Vb = 59.6 /-104° • Vc = 59.6 /104°
Analysis Results in These Sequence Quantities • Va0 = -5.4 • Va1 = 42.9 • Va2 = -24.1
The Synthesis Equation Results in the Original Unbalanced Voltage
Three phase fault Positive Phase to phase fault Positive Negative Phase to ground fault Positive Negative Zero Symmetrical Components Present During Shunt Faults
Symmetrical Component Review of Faults Types • Let’s return to the example fault reports and view the sequence quantities present
Single Line to Ground Fault • Voltage • Negative and zero sequence 180 out of phase with positive sequence • Current • All sequence are in phase