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Gay-Lussac’s Law

VIDEO. Gay-Lussac’s Law. P. There is a direct relationship between the temperature and pressure of a gas (if one increases so does the other) If volume is held constant: P 1 = P 2 T 1 T 2. Temperatures must be in Kelvin!.

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Gay-Lussac’s Law

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  1. VIDEO Gay-Lussac’s Law P • There is a direct relationship between the temperature and pressure of a gas (if one increases so does the other) • If volume is held constant: • P1 = P2 T1 T2 Temperatures must be in Kelvin! KMT – increasing the temperature gets the particles moving faster causing an increase in the number and energy involved in collisions; thus an increase in pressure

  2. Example • A gas exerts 1.2 atm of pressure. If the temperature is raised from 25oC to 100oC, find the new pressure. P1 = P2 T1 T2 P1 = T1 = P2 = T2 = 1.2atm 298K 1.2atm = P 298K 373K P = 1.5 atm ? 373K

  3. A fixed volume of gas exerts a pressure of 1.00 atm at a temperature of 25ºC. What is the pressure of the gas when it is heated to 100ºC? iRespond Question Multiple Choice F A.) 0.250 atm P = P T T 1atm = P 298K 373K B.) 1.25 atm C.) 2.50 atm D.) 4.00 atm E.)

  4. Which will always decrease the volume of a sample of methane gas which occupies a volume of 2.4 L at 25 °C? iRespond Question Multiple Choice F A.) An increase in pressure and an increase in temperature B.) A decrease in pressure and a decrease in temperature C.) An increase in pressure and a decrease in temperature D.) A decrease in pressure and an increase in temperature E.)

  5. Try To Explain This! The water vapor is removed when cooling causing a decrease in pressure inside the can. The internal pressure is no longer able to resist the atmospheric pressure, causing a collapse.

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