220 likes | 397 Views
Equations of Motion . September 15 Part 1. Continuum Hypothesis. Assume that macroscopic behavior of fluid is same as if it were perfectly continuous Newton’s 2 nd Law: Acceleration of a particle is proportional to the sum of the forces acting on that particle F=ma. N. y, v. z, w. x, u.
E N D
Equations of Motion September 15 Part 1
Continuum Hypothesis • Assume that macroscopic behavior of fluid is same as if it were perfectly continuous • Newton’s 2nd Law: Acceleration of a particle is proportional to the sum of the forces acting on that particle F=ma
N y, v z, w x, u R-H Cartesian f-plane or b-plane W x: eastward direction u: eastward velocity y: northward direction v: northward velocity z: local vertical w: vertical velocity R: vector distance from center of earth W: Earth’s rotation vector R
x-component of acceleration: or, for fluids: Other components:
Important kinds of forces acting on a fluid particle: • Wind stress • Gravitational • Pressure gradient • Frictional • Coriolis
Acceleration • Two kinds: - Particle acceleration – acceleration measured following a particle (Langrangian) - Local acceleration – acceleration seen at a fixed point in space (Eulerian)
A B vel. u dist. x Particle undergoes acceleration, but velocity measured at point A or B would not change with time
local acceleration + field acceleration particle accerleration
y u A v x At point A, if there were no other forces, we would see a local acceleration due to movement of the velocity field
Figure 7.2 in Stewart Consider the flow of a quantity qin into and qout out of the small box sketched in Figure 7.2. If q can change continuously in time and space, the relationship between qin and qout is
Coriolis • Coriolis arises because we measure a relative to coordinates fixed to the surface of a rotating earth i.e. accelerating – easier to measure
The acceleration of a parcel of fluid in a rotating system, can be written: R = vector distance from the center of the Earth Ω = angular velocity vector of Earth u = velocity of the fluid parcel in coordinates fixed to Earth (2Ω × u) = the Coriolis force Ω × (Ω × R) = centrifugal acceleration Coriolis and centrifugal accelerations are “Fictitious” – arise only because of choice of coordinate frame Coriolis exists only if there is a velocity – no velocity, no “force”
Gravity Term in Momentum Equation The gravitational attraction of two masses M1 and m is R = distance between the masses G = gravitational constant Fg = vector force along the line connecting the two masses force per unit mass due to gravity is ME = mass of the Earth
Adding the centrifugal acceleration to previous equation gives gravity g Figure 7.4 in Stewart
Momentum Equation in Cartesian Coordinates incompressible – no sound waves allowed
Derivation of Pressure Term Consider the forces acting on the sides of a small cube of fluid (Figure 7.3). The net force δFx in the x direction is But Therefore
Divide by the mass of the fluid (δm) in the box, the acceleration of the fluid in the x direction is
Can solve for u, v, w, p as a function of x, y, z, t • Need boundary conditions: - u, v, w, p must behave at boundaries i.e. no flow through boundaries no “slip” along boundaries