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Ion Concentration

Ion Concentration. 1. What is the concentration of each ion in a 0.300 M AlCl 3 solution?. 0.300 M AlCl 3. AlCl 3. +. Al 3+. 3Cl -. Cl -. 0.300 M. 0.300 M. 0.900 M. Cl -. Al 3+. Cl -.

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Ion Concentration

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  1. Ion Concentration

  2. 1. What is the concentration of each ion in a 0.300 M AlCl3 solution? 0.300 M AlCl3 AlCl3 + Al3+ 3Cl- Cl- 0.300 M 0.300 M 0.900 M Cl- Al3+ Cl-

  3. 2. What is the concentrationof each ion in the solution formed by dissolving 80.0 g ofCaCl2in 600.0 mL of water? 1 mol x 80.0 g 111.1 g [ CaCl2 ] = = 1.20 M 0.6000 L CaCl2 Ca2+ + 2Cl- 1.20 M 1.20 M 2.40 M

  4. 3. If 1.25 L of0.560 M Aluminum sulphate solution is added to 4.75 Lofwater, what is the resulting concentration of each ion? M1V1 = M2V2 (0.560 M)(1.25 L) = M2(6.00 L) M2 = 0.11666 M 2Al3+ Al2(SO4)3 + 3SO42- 0.11666 M 0.233 M 0.350 M x 3/2 Shortcut Al2(SO4)3 →2Al3+ + 3SO42- x 3/2 1.25 6.00 0.560 M x 2 0.233 M 0.350 M

  5. 4. If the [SO42-] = 0.100 M in 20.0 mL of Ga2(SO4)3, determine the [Ga3+] and the molarity of the solution. Ga2(SO4)3 2 Ga3+ + 3SO42- 0.0333 M 0.0667 M 0.100 M

  6. 5. If the [Cl-] = 0.400 M, calculate the number of grams of AlCl3that would be dissolved in 3.00 L of water. AlCl3 Al3+ + 3Cl- 0.13333 M 0.400 M 133.5 g 3.00 L 0.13333 mol x 53.4 g x = 1 L 1 mol

  7. 6. If 40.0 mL of 0.400 M potassium chloride solution is added to 60.0 mL of 0.600 M calcium chloride, what is the resulting concentrationof eachion. KCl K+ + Cl_ 40.0 100.0 0.400 M 0.160 M 0.160 M CaCl2 Ca2+ + 2Cl_ 60.0 100.0 0.360 M 0.720 M 0.600 M [Cl_] = 0.720 M + 0.160 M = 0.880 M

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