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PS 18A. Giancoli Pg. 129 Question: 12, 13a, b, 14, 15 a b &c, 16, 18, 19 a, b, c, 20 Problems: 28, 30, 32, 36. (1) Question 12. M e doubles then D r is smaller, T is smaller both! 13a. Same force on earth and moon C (3) 13b. Moon accelerates more B.
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PS 18A Giancoli Pg. 129 Question: 12, 13a, b, 14, 15 a b &c, 16, 18, 19 a, b, c, 20 Problems: 28, 30, 32, 36
(1) Question 12. • Me doubles then D r is smaller, T is smaller both! • 13a. Same force on earth and moon C (3) 13b. Moon accelerates more B
(4) 14. The moon is mostly responsible for the tides because the moon has a greater relative change in pull from side to side because the distances are greater compared to the distance to the pulling body. C www.mmscrusaders.com/newscirocks/tides/tideanim.htm
15b. WHY? B Earth is greater radius at the equator. There’s no centripetal acceleration because it’s not moving with tangential velocity. 15c. B no, they will complement each other. (5) 15a. Fg is more at the poles than at the equator. A
(8) 16. The moon isn’t pulled away from the earth because D • Same average radius to sun • Same average acceleration around sun • Same average period around sun
(9) 18. Which way should you launch the satellite? • EAST! A Because they’re already moving east (with the earth) so why fight it?
(10) 19a. Your apparent weight is • Greatest A when the elevator accelerates upwards • Smallest when the elevator is in free fall C • Same as usual when the elevator moves with constant v D http://mrwaynesclass.com/teacher/NewtonsLaws/weightlessness/home.html
(13) 20.Why does a satellite remain in orbit? Due to Fg and tangential speed A
(14) Problem 28 • Fg=Gm1m2 = 6.67x10-11(1350 kg)(5.98x1024) r2 ((6.38x103)(1000))2 Fg= 1470 N D
(15) 30. • g= Gm1/r2= 6.67x10-11(7.35x1022)/1.74x106 • g= -1.62m/s2 D
(16) 32. • 1.66 times the mass means 1.66 times the acceleration due to gravity. • 9.8 ( 1.66) = 16.3 m/s2
(17) 36. • g= G m/r2 = 6.67x10-11 (5) (1.99x1030)/100002 • g= 6.6 x1012 m/s2 or 7x1012 m/s2