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Exponential Function 5 Item MCQ

Exponential Function 5 Item MCQ. ANSILUZ H. BETCO San Bartolome High School. NEXT. Directions. Read and analyze the following questions properly. Click on the correct answer. BACK. NEXT. 1 . Which of the following define an exponential function?. BACK. NEXT.

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Exponential Function 5 Item MCQ

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  1. Exponential Function5 Item MCQ ANSILUZ H. BETCO San Bartolome High School NEXT

  2. Directions Read and analyze the following questions properly. Click on the correct answer. BACK NEXT

  3. 1. Which of the following define an exponential function? BACK NEXT a) 2x2 + 3x – 6= 8 b) 2/3 m – 5 = 15 c) y = 2x + 1 d) p3 + 2p -3 = 0

  4. Correct!! Feedback to Q1 BACK

  5. Exponential Function Definition: → If a>0 and a ≠ 1,then the exponential function with the base a is a function defined by f(x) = ax, where x is any real numbers. → therefore y= 2x +1 is the only equation wherein the exponent x vary. NEXT

  6. 2) Which of the following graphs represent an exponential function? a)b) d) c) BACK NEXT

  7. Correct!! Feedback to Q2 BACK

  8. Graph of Exponential Function The graph of y = ax is upward-sloping, and increases faster as x increases. The graph always lies above the x-axis but can get arbitrarily close to it for negative x; thus, the x-axis is a horizontal asymptote. The slope of the graph at each point is equal to its y coordinate at that point. NEXT

  9. 3) Solve for x: 93x = (1/3)5-x a) x = 1 b) x = -1 c) x = 2 d) x = -2 BACK NEXT

  10. Correct!! Feedback to Q3 BACK

  11. 3) 93x = (1/3)5-x • Solution 93x = (1/3)5-x 32(3x)= 3-1(5-x) change the equation with same base 6x = -5+x bring down the exponents 5x = -5 solve for x x = -1 answer NEXT

  12. 4) A certain city has a population of 20000 and a growth rate of 3.5%.What will be the expected population after 3 years? • 24,145 • 23,501 • 23,219 • 22,174 BACK

  13. Correct!! Feedback to Q4 BACK

  14. The Exponential Growth is in the form Y = P( 1 + r)xwhere P = original number r = rate of change x = unit of time y = total number after x years So, P = 20000 r = 3.5% or 0.035 t = 3 years Substitute Y = P( 1 + r)x = 20,000 (1 + .035)3 = 20,000 (1.035)3 = 20,000 (1.1087) = 22,174 expected population after 3 yrs NEXT

  15. 5) If a car depreciates at an annual rate of 15%, how much would be its value at the end of two years if its cost is $450,000 when new? a) $325,125 b) $276,356c) $315,134d) $412,300 BACK

  16. Correct!! Feedback to Q5 BACK

  17. The Exponential Decay is in the form Y = P( 1 - r)xwhere P = original amount r = rate of change x = unit of time y = total amount after x years So, P= $450,000 r = 15% or 0.15 t= 2 years Substitute Y = P( 1 - r)x = 450,000 (1 - .15)2 = 450,000 (0.85)2 = 450,000 (0.7225) = $325,125 amount of car after 2 years NEXT

  18. i'm sorry Try again !

  19. i'm sorry Try again !

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