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A sample of helium gas is collected at room temperature in a 4.5 L balloon at STP. The balloon is then submerged in a tub of water, also at room temperature, such that the external pressure is increased to 110.2 kPa. What will the final volume of the balloon become? Step 1. What information is given? Initial pressure: (Pi) = 101.3 kPa (standard pressure) Initial volume: (Vi) = 4.50L Final pressure: (Pf) = 110.2 kPa
Step 2. Use the equation: PiVi = PfVf PiVi = PfVf Substitute the values (101.3 kPa) (4.50 L) = (110.2 kPa)(Vf) To solve for Vf, divide both sides by 110.2kPa = Vf = 4.14 L (101.3kPa)(4.50L) (110.2kPa) Vf
Example 2: A 45.6 mL sample of gas at 490 torr is compressed to a certain volume at 3 atm. What is the new volume in litres?