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2 a) possible additional sources of error (creep test)

2 a) possible additional sources of error (creep test). temperature not constant over time light ( optical strain gages !) may be not constant humidity (sample affected !) not constant load or displacement may not be const . machine / instrument creeping creeping of strain gage

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2 a) possible additional sources of error (creep test)

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  1. 2 a) possible additional sources of error (creep test) • temperature not constantover time • light (opticalstraingages!) maybe not constant • humidity (sample affected!) not constant • loadordisplacementmay not beconst. • machine/instrumentcreeping • creepingofstraingage • etc. (day / night!)

  2. 2 b) Analyzing a creep experiment tertiary secondary primary

  3. creepcompliance notethatthevaluesofearegiven in %, so youhavetodividethemby 100 to evaluatecreepcomplianceisonlyuseful in thesecondaryregion (markedby ) D is in therangeof 1/MPa

  4. 2 c) i. time-temperature-shift for master curve at 120°C

  5. 2 c) i. result: mastercurveat 120°C mastercurveat 120°C

  6. 2 c) ii. predictcompliance after 5 days mastercurveat 120°C

  7. mastercurveat 120°C 5 d = 5*24*60 min = 7200 min

  8. D(5 d) ≈ 1/psi mastercurveat 120°C 5 d = 5*24*60 min = 7200 min

  9. 2 c) iii. possiblepredictionrangeat 120°C mastercurveat 120°C

  10. mastercurveat 120°C 40000 min = = 0,9 months = = 0,1 years

  11. forcomparison: possiblepredictionrangeat 90°C mastercurveat 90°C 3e+9 min = = 70000 months = = 5700 years

  12. 3. Fatiguetesting a) threeexamplesofapplicationscyclic stress loading wingsofairplanes turbine blades rotor blades (nicht sehr schwer, wenn zwei davon schon in b) genannt sind)

  13. b) Wöhler curveandestimationoflife time

  14. b) Wöhler curveandestimationoflife time (aim: toshowthatcyclicloadedcomponents must havehugesafety factors, iffatiguetestingis not performed) i. N(40 MPa) ≈ 9000 ii. N(27 MPa) ≈ 300000 i. N(40 MPa) ≈ 9000 tlife = N/f = 9000 * 1 / 0,5 s = 18000 s = = 5 hours ii. N(27 MPa) ≈ 300000 tlife = N/f = 300000 * 1 / 1000 s = 300 s = = 5 minutes

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