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NM Standards: AFG.C.5, GT.A.5, GT.B.4, DAP.B.3. Any point that is on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. M. B. N. B. M. P. D. If is an angle bisector, then PM = PN. P. A. C. N. D. A. C.
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Any point that is on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. M B N B M P D If is an angle bisector, then PM = PN P A C N D A C If PM = PN, then is an angle bisector. Any point equidistant from the endpoints of a segment lies on the perpendicular bisector of the segment. • Any point on the angle bisector is equidistant from the sides of the angle. • Any point equidistant from the sides of an angle lies on the angle bisector. Remember, distance is always measured on the perpendicular.
Definitions Point of Concurrency - A common point in which three or more lines intersect Circumcenter - The intersection point of the three perpendicular bisectors of a triangle Incenter - The intersection point of the three angle bisectors of a triangle Centroid - The intersection point of the three medians of a triangle Orthocenter - The intersection point of the three altitudes of a triangle
Theorems Circumcenter Theorem- The circumcenter of a triangle is equidistant from the vertices of the triangle Incenter Theorem- The incenter of a triangle is equidistant from each side of the triangle Centroid Theorem- The centroid of a triangle is two-thirds the distance of its corresponding median of the triangle
Example 1-2a ALGEBRA Points U, V, and W are the midpoints of respectively. Find a,b, and c. Find a. Segment Addition Postulate Centroid Theorem Substitution Multiply each side by 3 and simplify. Subtract 14.8 from each side. Divide each side by 4.
Example 1-2a Find b. Segment Add Postulate Centroid Theorem Find c. Segment Addition Postulate Centroid Theorem
Example 1-2b ALGEBRA Points T, H, and G are the midpoints of respectively. Find w,x, and y. Answer: