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p*Ni><k s>²yin) smj

p*Ni><k s>²yin) smj. p*Ni<>k s>²yini[ p(rcy. p*Ni<>k s>²yini[ p(rcy. ki[e pN Fn k[ äN s>²yin[ p*Ni<>k s>²yi kh[ C[. …, -6, -5, -4, -3, -2, -1, 0, +1, +2, +3, +4, +5, +6, … s>²yir[Ki pr dr[k äN p*N<ik an[ Fn p*Ni<k s>²yin) ji[D Y) 0 Y) srKi a>tr[ aiv[l) C[. 0. 1. 2. -3. -2. 3.

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p*Ni><k s>²yin) smj

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  1. p*Ni><k s>²yin) smj

  2. p*Ni<>k s>²yini[ p(rcy

  3. p*Ni<>k s>²yini[ p(rcy • ki[e pN Fn k[ äN s>²yin[ p*Ni<>k s>²yi kh[ C[. …, -6, -5, -4, -3, -2, -1, 0, +1, +2, +3, +4, +5, +6, … • s>²yir[Ki pr dr[k äN p*N<ik an[ Fn p*Ni<k s>²yin) ji[D Y) 0 Y) srKi a>tr[ aiv[l) C[. 0 1 2 -3 -2 3 -1

  4. p*Ni<>k s>²yini[ p(rcy • aipN[ p*Ni<k s>²yin[ lil an[ p)Li (cM oiri dSi<v)S&>. • lil vt&<L äN p*Ni<k s>²yi dSi<v[ C,[ jyir[ p)L& vt&<L Fn p*Ni<k s>²yi dSi<v[ C[. Fn p*Ni<>k äN p*Ni<>k

  5. p*Ni<>k s>²yini[ p(rcy • n)c[n) aikZ(t -3 n[ 2 r)t[ dSi<vvin) r)t btiv[ C[. • -3 n[ 2 Y) vFir[ r)t[ pN dSi<v) Skiy. -3 -3

  6. p*Ni<>k s>²yini[ p(rcy • dr[k vt&<Lni[ sm&h kyi[ p*Ni<k dSi<v[ C[ t[ khi[? +1 -2 +2 jvib

  7. p*Ni<>k s>²yini[ p(rcy • ji[ lil an[ p)Li vt&<Ln) s>²yi a[k srK) hi[y ti[ t[ ke s>²yi dSi<v[ C[? • t[ 0 {S*ºy} dSi<v[ C[.

  8. srviLi[ an[ bidbik)

  9. p*Ni<>k s>²yini[ srviLi[ • aipN[ p*Ni<>k s>²yini srviLin[ vt&<Lni nm&ni Wiri smJa[. • -2 n[ ai[Ci mi ai[Ci vt&<L vD[ dSi<vi[. • +5n[ ai[Cimi> ai[Ci vt&<L vD[ dSi<vi[.

  10. p*Ni<>k s>²yini[ srviLi[ • 2 r>gni vt&<Lni sm&hi[n[ B[gi krviY) t[ ke s>²yi dSi<v[ C[? • n)c[n&> viky j[ s>²yi dSi<v[ C[ t[ lKi[. • -2 + +5 = +3 +3

  11. p*Ni<>k s>²yini[ srviLi[ • dr[k diKlini[ jvib Si[Fvi miT[ lil an[ p)Li vt&<Lni[ upyi[g kri[. -2 + -3 = ? jvib = -5 + -2 + -3 = -5

  12. p*Ni<>k s>²yini[ srviLi[ -6 + +2 = ? jvib + - 4 = -6 + +2 = -4 -3 + +4 = ? jvib +1 = + -3 + +4 = +1

  13. p*Ni<>k s>²yin) bidbik) • aipN[ GN)vir bidbik) n[ “d*r le jv&>” a[m gN)a[ C)a[. • gNtr) miT[ ke aikZ(t upyi[g) YS[? +3 - +5 = ? +3 +3

  14. p*Ni<>k s>²yin) bidbik) • ai aikZ(t +3 dSi<v[ C[ an[ aipN[ t[mi>Y) +5 ai[Ci kr) Sk)a[ C)a[ • jyir[ aipN[ 5 p)Li vt&<Ln[ ai[Ci kr)a[ , Ryir[ aipN) pis[ 2 lil vt&<L bik) rh[S[. aipN[ ai aikZ(t mi>Y) 5 p)Li vt&<L n[ d*r nh)> kr) Sk)a [, kirN k[ vt&<L ai[Ci C[.

  15. p*Ni<>k s>²yin) bidbik) • aip[l bidbik)ni diKli lil an[ p)Li vt&<L vipr)n[ kri[. -2 - -4 = ? jvib

  16. p*Ni<>k s>²yin) bidbik) hv[ tm[ 4 lil vt&<Ln[ d*r le je ai[Ci kr)Ski[ 2 p)Li vt&<L bik) rh[S[ t[Y) jvib....2 ai dSi<v[ C[ k[ -2 vt&<Lmi>Y) -4 vt&<L le jvi miT[ p&rti nY) hv[ ji[ tm[ 2 lil an[ 2 p)Li vF& vt<L um[rSi[ {S*ºy um[rv&>} ti[ tmir) pis[ k&l 4 lil vt&<L YS[ an[ hj& s&F) -2 vt&<L dSi<vS[. -2 - -4 = +2

  17. p*Ni<>k s>²yin) bidbik) ai diKli[ gNi[. +3 - -5 = ? jvib

  18. p*Ni<>k s>²yin) bidbik) • p*rti p\miNmi> lil an[ p)Li vt&<Ln) ji[D um[rviY) tm[ 5 lil vt&<Ln[ ai[Ci kr) SkSi[ • 5 lil vt&<L ai[Ci krviY) tmir) pis[ 8 p)Li vt&<L bik) rh[S[. +3 - -5 = +8

  19. p*Ni<>k s>²yin) bidbik) ai diKli[ gNi[. -3 - +2 = ? ANSWER

  20. p*Ni<>k s>²yin) bidbik) • b[ lil an[ p)Li vt&<Ln) ji[D um[ri[ j[Y) tm[ 2 p)Li vt&<Ln[ ai[Ci kr) Ski[. • 2 p)Li vt&<L ai[Ci krviY) tmir) pis[ 5 lil vt&<L rh[S[. -3 - +2 = -5

  21. p*Ni<>k s>²yin) bidbik) 3 a[k srK) s>²yini[ upyi[g kr)n[ viAt(vk s>²yi vD[ 4 sici sm)krNi[ mL[ C[. u.di. tr)k[ 7 + 8 = 15 8 + 7 = 15 15 – 7 = 8 15 – 8 = 7 ai bFij vikyi[ sici C[.

  22. p*Ni<>k s>²yin) bidbik) aipN[ viAt(vk s>²yigNn[ pN p*Ni<>k s>²yi siY[ upyi[g kr) Sk)a[ C)a[ ai viAt(vk s>²yin) ckisN) miT[ tmiri lil an[ p)Li vt&<Lni[ upyi[g kri[ -3 + +8 = +5 +8 + -3 = +5 +5 - + 8 = -3 +5 - - 3 = +8

  23. p*Ni<>k s>²yiai[ni[[ g&Nikir

  24. g&Nikir • lil an[ p)Li vt&<L ni[ nm&ni tr)k[ upyi[g kr)n[ g&Nikir kr) Skiy. • yid riKi[ g&Nikirn[ vir>vir Yt) srviLin) (k\yi tr)k[ vN<v) Skiy C[. • t[Y) 2 x 3 = ? 3vt&<Lni 2 sm&h = 6 vt&<L

  25. g&Nikir • 2 x -3 a[Tl[ -3 ni 2 sm&h 2 x -3 = -6

  26. g&Nikir • jyir[ 2 x 3 = 6 an[3 x 2 = 6 hi[y ti[ S&> a[ sic& C[ k[ -3 x 2 = -6 ? • -3 x 2 = -6 sic& C[ • +2 x -3 = -6 an[-3 x +2 = -6 a[ viAt(vk s>²yism&hni s¿yi[ C[. +2 x -3 = -6 -3 x +2 = -6 -6 ÷ +2 = -3 -6 ÷-3 = +2

  27. g&Nikir • aip[l dr[k g&Nikirni diKli vt&<Ln[ nm*ni tr)k[ upyi[g kr)n[ kri[. • +2 x +4 = ? +4 ni 2 sm*h jvib +2 x +4 = +8

  28. g&Nikir • +3 x -3 = ? jvib -3 ni 3 sm&h +3 x -3 = -9

  29. g&Nikir jvib • -2 x +4 = ? -2ni 4 sm&h -2 x +4 = -8 viAt(vk s>²yiai[ni[ upyi[g kr)n[ dSi<vi[ -2 x +4 = ?  aipN[ -2 ni +4 sm&h ni dSi<v) Sk)a[. +4 x -2 = ?  aipN[ 4 ni -2 sm&h dSi<v) Sk)a[.

  30. g&Nikir • +1, -1 (v@¹F s>²yi C[. jvib (v@¹F s>²yi aivS[. • +2 an[-2 a[ b>ºn[ a[kb)jin) (v@¹F s>²yi C[. • +2 x -3 an[ -2 x -3 b>n[ ni[ jvib (vri[F) s>²yi C[. +1 x +3 = +3 -1 x +3 = -3

  31. g&Nikir • -2 x -3 n[ dSi<vvi miT[ -3 n) (v@¹F s>²yi ni 2sm&hni[ upyi[g krvi[. -2 x -3 = +6

  32. g&Nikir • -3 x -4 ni[ S&> jvib aivS[ t[ dSi<vvi miT[ vt&<Lni[ upyi[g kri[ jvib +4 ni 3 sm&h {-4 ni (vr[iF)} -3 x -4 = +12

  33. p*Ni<>k s>²yini Bigikir

  34. Bigikir • +12 ÷ +3 ni[ jvib vt&<Lni[ upyi[g kr) Si[Fi.[ dr[k sm*hmi> 4 p)Li vt&<L C[. 12 p)Li vt&<Ln[ 3 a[k srKi sm*hmi> (vBiJt kri[ +12 ÷+3 = +4

  35. Bigikir • -15 ÷ +5 ni[ jvib vt&<Lni[ upyi[g kr) Si[Fi.[ -15 n[ 5 a[k srKi sm&hmi> (vBiJt kri[. -15 ÷+5 = -3

  36. Bigikir • viAt(vk s>²yism&h lKi[. • -4 x +2 = -8 • tmiri jvib srKivi[. • +2 x -4 = -8 • -8 ÷ +2 = -4 • -8 ÷ -4 = +2

  37. Bigikir • n)c[ni dr[k jvib Si[Fvi miT[ lil an[ p)Li vt&<Lni[ upyi[g kri[. 1) -2 + -8 5) +3 x -4 2) +6 + -4 6) -5 x -2 3) -5 - +4 7) -12 ÷ +6 4) -6 - -7 8) -8 ÷ +2 jvib

  38. Bigikir 1) -2 -8 = -10 + 2) +6 -4 = +2 +

  39. Bigikir 3) -5 +4 = -9 - 4) -6 -7 = +1 -

  40. Bigikir 5) +3 x -4 = -12 6) -5 x -2 = +10 -2 n)(v@´F s>²yini 5 sm*h C[.

  41. Bigikir -12 n[ 6 a[k srKi sm*hmi> vh[>cvimi> aiv[l C[. 7) -12 ÷+6 = -2 8) -8 ÷+2 = -4 4 a[k srKi sm*hmi> vh[cvimi> aiv[l C[.

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