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Vertical Circles and Curves. Rounding A Curve. Friction between the tires and the road provides the centripetal force needed to keep a car in the curve. Example.
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Rounding A Curve • Friction between the tires and the road provides the centripetal force needed to keep a car in the curve
Example • A 1000 kg car rounds a curve on a flat road of radius 50 m at a speed of 14 m/s. A) will the car make the turn on a dry day when the μ is .60? B) What about on a day when the road is icy and the μ is .25?
Vertical Circle • Weight is acting in the same plane as centripetal force
Example • A .150kg ball on the end of a 1.10 m long cord is swung in a vertical circle a) determine the minimum speed the ball must have at the top of its arc so that it continues moving in a circle b) calculate the tension of the cord at the bottom of the swing if it is moving 2x the speed calculated in part a.
Solution • At top of swing centripetal force is a combination of mg and FT Fr = FT + mg - when just keeping it in a circle, we can assume that the FT = 0 and the centripetal force is supplied only by gravity
Example On a roller coaster, a 250kg car moves around a vertical loop of radius 15m with a speed of 13 m/s at the top of the loop and 22 m/s at the bottom of the loop. What weight will he feel at the top and the bottom?