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Chapter 21

Chapter 21. Colligative Properties: Part 2. Colligative Properties. Properties determined by the number of solute particles in solution rather than the type of particles . Vapor pressure lowering Boiling point elevation Freezing point depression Osmotic pressure. Boiling Point Elevation.

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Chapter 21

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  1. Chapter 21 Colligative Properties: Part 2

  2. Colligative Properties • Properties determined by the number of solute particles in solution rather than the type of particles. • Vapor pressure lowering • Boiling point elevation • Freezing point depression • Osmotic pressure

  3. Boiling Point Elevation ∆Tbp = (Kbp)(m)(#particles)

  4. Boiling Point Elevation ∆Tbp = (Kbp)(m)(#particles) # particles Molecular solutes always = 1 Example: C6H12O6 Ionic solutes = # of ions in the compound Example: BaCl2, Al2(SO4)3

  5. Freezing Point Depression ∆Tfp = (Kfp)(m)(#particles)

  6. Why is salt used on the roads instead of sugar?

  7. What is the freezing point of a 1.5m aqueous solution of NaCl? ∆Tfp = (Kfp)(m)(#particles) ∆Tfp = (1.853°C∙kg/mol)(1.5mol/kg)(2) ∆Tfp = 5.559°C New Freezing Point = 0.000°C – 5.559°C FP = -5.559°C

  8. What is the boiling point of a 2.4m aqueous solution Ba(NO3)2? ∆Tbp = (Kb)(m)(#particles) ∆Tbp = (0.515°C∙kg/mol)(2.4mol/kg)(3) ∆Tbp = 3.708°C New Boiling Point = 100.000°C + 3.708°C BP = 103.708°C

  9. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C

  10. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C A

  11. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C A

  12. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C A

  13. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C A

  14. 97.5g of C12H22O11 are dissolved in 185g of water. Find the freezing point and boiling point. FP = -2.854°C BP = 100.7931°C

  15. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C

  16. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C A

  17. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C A

  18. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C A

  19. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C A

  20. 14.0g of C10H8 are dissolved in 25.0g of benzene. Find the freezing point and boiling point. FP = -16.867°C BP = 91.169°C

  21. Homework • Finish Worksheet: Vapor Pressure, Boiling Point and Freezing Point.

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