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Hint. Straight Line. Find the equation of the line which passes through the point (-1, 3) and is perpendicular to the line with equation. Find gradient of given line:. Find gradient of perpendicular:. Find equation:. Next. Quit. Quit. Hint. Straight Line.
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Hint Straight Line Find the equation of the line which passes through the point (-1, 3) and is perpendicular to the line with equation Find gradient of given line: Find gradient of perpendicular: Find equation: Next Quit Quit
Hint Straight Line Find the equation of the straight line which is parallel to the line with equation and which passes through the point (2, –1). Find gradient of given line: Gradient of parallel line is same: Find equation: Previous Next Quit Quit
Use Hint Straight Line Find the size of the angle a° that the line joining the points A(0, -1) and B(33, 2) makes with the positive direction of the x-axis. Find gradient of the line: Use table of exact values Previous Next Quit Quit Table of exact values
Hint Straight Line A and B are the points (–3, –1) and (5, 5). Find the equation of a) the line AB. b) the perpendicular bisector of AB Find equation of AB Find gradient of the AB: Gradient of AB (perp): Find mid-point of AB Use gradient and mid-point to obtain perpendicular bisector AB Previous Next Quit Quit
Use Hint Straight Line The line AB makes an angle of radians with the y-axis, as shown in the diagram. Find the exact value of the gradient of AB. (x and y axes are perpendicular) Find angle between AB and x-axis: Use table of exact values Previous Next Quit Quit Table of exact values
Hint Straight Line A triangle ABC has vertices A(4, 3), B(6, 1) and C(–2, –3) as shown in the diagram. Find the equation of AM, the median from A. Find mid-point of BC: Find gradient of median AM Find equation of median AM Previous Next Quit Quit
Hint Straight Line P(–4, 5), Q(–2, –2) and R(4, 1) are the vertices of triangle PQR as shown in the diagram. Find the equation of PS, the altitude from P. Find gradient of QR: Find gradient of PS (perpendicular to QR) Find equation of altitude PS Previous Next Quit Quit
Find gradient of Find gradient of Hint Straight Line The lines and make angles of a and bwith the positive direction of the x-axis, as shown in the diagram. a) Find the values of a and b b) Hence find the acute angle between the two given lines. Find a° Find b° Use angle sum triangle = 180° Find supplement of b 72° Angle between two lines Previous Next Quit Quit
Hint Straight Line Triangle ABC has vertices A(–1, 6), B(–3, –2) and C(5, 2) Find: a) the equation of the line p, the median from C of triangle ABC. b) the equation of the line q, the perpendicular bisector of BC. c) the co-ordinates of the point of intersection of the lines p and q. (-2, 2) Find mid-point of AB Find gradient of p Find equation of p (1, 0) Find gradient of BC Find mid-point of BC Find gradient of q Find equation of q (0, 2) Solve p and q simultaneously for intersection Previous Next Quit Quit
Hint Straight Line Triangle ABC has vertices A(2, 2), B(12, 2) and C(8, 6). a) Write down the equation of l1, the perpendicular bisector of AB b) Find the equation of l2, the perpendicular bisector of AC. c) Find the point of intersection of lines l1 and l2 d) Hence find the equation of the circle passing through A, B and C. Perpendicular bisector AB Mid-point AB (5, 4) Find gradient of AC Find mid-point AC Equ. of perp. bisector AC Gradient AC perp. (7, 1) Point of intersection This is the centre of circle Find radius (intersection to A) Equation of circle: Previous Next Quit Quit
Hint Straight Line A triangle ABC has vertices A(–4, 1), B(12,3) and C(7, –7). a) Find the equation of the median CM. b) Find the equation of the altitude AD. c) Find the co-ordinates of the point of intersection of CM and AD Gradient CM (median) Mid-point AB Equation of median CM Gradient of perpendicular AD Gradient BC Equation of AD (6, -4) Solve simultaneously for point of intersection Previous Next Quit Quit
Hint Straight Line A triangle ABC has vertices A(–3, –3), B(–1, 1) and C(7,–3). a) Show that the triangle ABC is right angled at B. b) The medians AD and BE intersect at M. i) Find the equations of AD and BE. ii) Hence find the co-ordinates of M. Gradient BC Gradient AB Product of gradients Hence AB is perpendicular to BC, so B = 90° Gradient of median AD Equation AD Mid-point BC Gradient of median BE Equation AD Mid-point AC Solve simultaneously for M, point of intersection Previous Next Quit Quit
Straight Line Table of exact values Return