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PUNNETT SQUARES. Crosses Involving One Trait. PUNNETT SQUARE’S: CROSSES INVOLVING 1 TRAIT - #1. Black fur is dominant over brown fur. Predict the offspring’s geno. & pheno. whose parents are heterozygous for black fur. Trait: fur color. B= black b=brown. P1: Bb x Bb. B.
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PUNNETT SQUARES Crosses Involving One Trait
PUNNETT SQUARE’S: CROSSES INVOLVING 1 TRAIT - #1 Black fur is dominant over brown fur. Predict the offspring’s geno. & pheno. whose parents are heterozygous for black fur. Trait: fur color B= black b=brown P1: Bb x Bb B b Genotypes: 25% homozygous dominant (BB) 50% heterozygous black (Bb) 25% homozygous brown-recessive (bb) Phenotypes 75% black 25% brown B BB Bb b Bb bb
PUNNETT SQUARE’S: CROSSES INVOLVING 1 TRAIT - #2 Black fur is dominant over brown fur. Now do the same when one parent is homozygous black and the other is homozygous brown. Trait: fur color B= black b=brown P1: BB x bb b b Genotypes: 0% homozygous dominant (BB) 100% heterozygous black (Bb) 0% homozygous brown-recessive (bb) Phenotypes 100% black 0% brown B Bb Bb B Bb Bb
PUNNETT SQUARE’S: CROSSES INVOLVING 1 TRAIT - #3 Black fur is dominant over brown fur. Now do the same when one parent is heterozygous black and the other is homozygous brown. Trait: fur color B= black b=brown P1: Bb x bb b b Genotypes: 0% homozygous dominant (BB) 50% heterozygous black (Bb) 50% homozygous brown-recessive (bb) Phenotypes 50% black 50% brown B Bb Bb b bb bb
PRACTICING GENETICS #1 A blue heterozygous smurf is crossed with a red smurf. Red is recessive in smurfs Trait: skin color B= blue b=red P1: Bb x bb b b a) Bb, Bb, bb, bb b) blue, blue, red, red c) 0% homozygous dominant 50% heterozygous 50% recessive d) 50% blue 50% red B Bb Bb b bb bb
PRACTICING GENETICS #1 A homozygous brown turtle is crossed with a homozygous dominant green turtle. Trait: shell color G=green g=brown P1: gg x GG G G a) Gg, Gg, Gg, Gg b) green, green, green, green c) 0% homozygous dominant 100% heterozygous 0% recessive d) 0% brown 100% green g Gg Gg g Gg Gg
PRACTICING GENETICS #3 A recessive curly-tailed chipmunk is crossed with a heterozygos straight-tailed chipmunk Trait: tail type S = straight s = curly P1: ss x Ss S s a) Ss, ss, Ss, ss b) straight, curly, straight, curly c) 0% homozygous dominant 50% heterozygous 50% recessive d) 50% straight-tailed 50% curly tailed s Ss ss s Ss ss