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Reversible Reactions and Equilibrium

Reversible Reactions and Equilibrium. OBJECTIVES Describe how the amounts of reactants and products change in a chemical system at equilibrium. Identify three stresses that can change the equilibrium position of a chemical system.

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Reversible Reactions and Equilibrium

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  1. Reversible Reactions and Equilibrium • OBJECTIVES • Describe how the amounts of reactants and products change in a chemical system at equilibrium. • Identify three stresses that can change the equilibrium position of a chemical system. • Explain what the value of Keq indicates about the position of equilibrium.

  2. Reversible Reactions • Some reactions do not go to completion as we have assumed • They may be reversible – a reaction in which the conversion of reactants to products and the conversion of products to reactants occur simultaneously • Forward: 2SO2(g) + O2(g)→ 2SO3(g) • Reverse: 2SO2(g) + O2(g)← 2SO3(g)

  3. Reversible Reactions • The two equations can be combined into one, by using a double arrow, which tells us that it is a reversible reaction: 2SO2(g) + O2(g)↔ 2SO3(g) • A chemical equilibrium occurs, and no net change occurs in the actual amounts of the components of the system.

  4. Reversible Reactions • Even though the rates of the forward and reverse are equal, the concentrations of components on both sides may not be equal • An equilibrium position may be shown: A B or A B 1% 99% 99% 1% • Note the emphasis of the arrows direction • It depends on which side is favored; almost all reactions are reversible to some extent

  5. Le Chatelier’s Principle • The French chemist Henri Le Chatelier (1850-1936) studied how the equilibrium position shifts as a result of changing conditions • Le Chatelier’s principle: If stress is applied to a system in equilibrium, the system changes in a way that relieves the stress

  6. Le Chatelier’s Principle • What items did he consider to be stress on the equilibrium? • Concentration • Temperature • Pressure • Concentration – adding more reactant produces more product, and removing the product as it forms will produce more product

  7. Le Chatelier’s Principle • Temperature – increasing the temperature causes the equilibrium position to shift in the direction that absorbs heat • If heat is one of the products (just like a chemical), it is part of the equilibrium • so cooling an exothermic reaction will produce more product, and heating it would shift the reaction to the reactant side of the equilibrium: C + O2(g)→ CO2(g) + 393.5 kJ

  8. Le Chatelier’s Principle • Pressure – changes in pressure will only effect gaseous equilibria • Increasing the pressure will usually favor the direction that has fewer molecules N2(g) + 3H2(g)↔ 2NH3(g) • For every two molecules of ammonia made, four molecules of reactant are used up – this equilibrium shifts to the right with an increase in pressure

  9. Equilibrium Constants: Keq • Chemists generally express the position of equilibrium in terms of numerical values, not just percent • These values relate to the amounts (Molarity) of reactants and products at equilibrium • This is called the equilibrium constant, and abbreviated Keq

  10. Equilibrium Constants • consider this reaction (the capital letters are the chemical, and the lower case letters are the balancing coefficient): aA + bB  cC + dD • The equilibrium constant (Keq) is the ratio of product concentration to the reactant concentration at equilibrium, with each concentration raised to a power (which is the balancing coefficient).

  11. Equilibrium Constants • consider this reaction: aA + bB  cC + dD • Thus, the “equilibrium constantexpression” has this general form: [C]c x [D]d [A]a x [B]b (brackets: [ ] = molarity concentration) Note that Keq has no units on the answer; it is only a number because it is a ratio Keq =

  12. Equilibrium Constants • the equilibrium constants provide valuable information, such as whether products or reactants are favored: • if Keq > 1, products favored at equilibrium • if Keq < 1, reactants favored at equilibrium • if Keq = 1, the amounts of product and reactants will be approximately equal

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