1 / 8

The General Gas Equation Combined Gas Law

=. P 1 V 1. P 2 V 2. n 1 T 1. n 2 T 2. The General Gas Equation Combined Gas Law. Ideal Gas Equation. nT. V . P. Combining the Gas Laws: The Ideal Gas Equation is derived using the Ideal Gas Constant. Boyle’s law V  1/P Charles’s law V  T Avogadro’s law V  n. nT.

blythe-garza
Download Presentation

The General Gas Equation Combined Gas Law

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. = P1V1 P2V2 n1T1 n2T2 The General Gas EquationCombined Gas Law

  2. Ideal Gas Equation

  3. nT V  P Combining the Gas Laws: The Ideal Gas Equation is derived using the Ideal Gas Constant • Boyle’s law V  1/P • Charles’s law V  T • Avogadro’s law V  n nT V = R P PV = nRT

  4. PV R= nT = 0.08206 L atm/mol K The Gas Constant PV = nRT = 1.207 L psi / mol K = 8.314 Pa m3 / mol K = 8.314 J/mol K = 62.36 L Torr/ mol K

  5. = P1V1 P2V2 n1T1 n2T2 The General Gas Equation R=

  6. Example A 5.0 L cylinder contains oxygen gas at 20.0°C and 735 mm Hg. How many grams of oxygen are in the cylinder? Catalog Variables P = 735 mmHg V = 5.0 L n = # moles O2 R = 0.08206 L atm / mol K T = 20 °C

  7. Example Convert Units V = 5.0 L n = # moles O2 R = 0.08206 L atm / mol K T = 20 °C + 273 = 293 K Solve Equation = 0.201 mol O2

  8. m n = and MM m RT PV = MM Molar Mass Determination PV = nRT m RT m RT MM = MM = PV PV P MM dRT d= MM = RT P

More Related