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Combined Gas Law. Agenda Demos & Notes on gas laws Homework: Gas Laws. Combined Gas Law. Date:. Kinetic Molecular Theory. The theory that a gas consists of molecules in constant random motion. Postulate 1.
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Combined Gas Law Agenda • Demos & Notes on gas laws • Homework: Gas Laws
Combined Gas Law Date:
Kinetic Molecular Theory The theory that a gas consists of molecules in constant random motion.
Postulate 1 • Gases are composed of molecules whose size is negligible compared with the average distance between them.
Postulate 2 • Molecules move randomly in straight lines in all directions and at various speeds. • Pressure is the same in all directions • Changes directions when it collides
Postulate 3 • The forces of attraction or repulsion between two molecules in a gas are very weak or negligible, except when they collide.
Postulate 4 • When molecules collide with one another, the collisions are elastic.
Postulate 5 • The average kinetic energy of a molecule is proportional to the absolute temperature.
Variables • P: pressure • V: volume • T: temperature – must be in Kelvin • Celsius, oC and Kelvin • oC + 273 = K
Pressure • Force exerted per unit of area • Has multiple units: psi, kg/ms2 = pascal, mmHg = torr, atm. • Evagelista Torricelli created the mercury barometer
Standard Pressure • 1 atm = 760 torr = 760 mmHg = 101.3 kPa • Convert between units using std pressures as conversion factors.
Temperature • Measure of the average kinetic energy of the molecules.
Volume • The space occupied by matter • For which state of matter can the volume be changed simply by changing the pressure or temperature?
What does a vacuum pump do? Decreases the pressure by removing air molecules
Observe the balloon and marshmallow. What is the relationship between pressure and volume?
Modified Volcano • Vinegar and baking soda make CO2. • As more MC of gas are created, pressure increases and it needs more volume. • Stopper blows
Boyles Law • P1V1 = P2V2 • Pressure varies inversely with volume.
This little light of mine • Flame burning = high T, MC moving fast = high P and take up more space. • Cover with graduated cylinder, use up all O2 flame goes out instantly reducing T. • Less movement, less pressure. • Atm forces liquid up!
Gay – Lussac Law • P1T2 = P2T1 • Pressure varies directly with temperature. • Temperature MUST be in Kelvin and is not used to determine SF.
Hand Warmer • Cold jar, balloon deflated • Warm jar, increase T, volume of balloon increases.
Charles Law • V1T2 = V2T1 • Volume varies directly with temperature. • Temperature MUST be in Kelvin and is not used to determine SF.
Fountain • Increase pressure in container, by decreasing space between gas molecules. • Stop blowing, releases pressure and creates more space by spraying water!
Combined Gas Law • P1V1T2 = P2V2T1 • Shows the relations between variables and predicts results of adjustments made to system. • Use for changing conditions! • If one variable is constant, enter the same value twice or remove that variable from the equation.
STP Conditions • Standard temperature is 273 K • Standard pressure can be • 1 atm • 101.3 kPa • 760 torr • 760 mmHg
V1 P1 A 50. L sample of a gas at a pressure of 1.0 atm and a temperature of 25oC is moved to an area where the pressure is 5.0 atm and the temperature is 30oC. What is the new volume of the gas? T1 P2 T2 • P1V1T2 = P2V2T1 • (1.0atm)(50.L)(30+273K) = (5.0atm)(X)(25+273) • 15150 = 1490X • 10. L
V1 P1 A 50.0 mL sample of a gas has a pressure of 2.00 atm when the temperature is 25oC. What volume will the gas occupy at a pressure of 4.00 atm when a constant T? T1 P2 • P1V1T2 = P2V2T1 • (2.00atm)(50.0mL) = (4.00atm)(X) • 100 = 4X • 25.0 L
V1 T1 P1 A 5.0 mL sample at 20oC has a pressure of 1.0 atm. What volume will the gas occupy when the temperature is raised to 60oC at constant pressure? T2 • P1V1T2 = P2V2T1 • (5.0mL)(60+273) = (X)(20+273) • 1665 = 293X • 5.7 mL
P1 V1 A 20.0 mL sample of a gas has a pressure of 2.0 atm at a temperature of 20oC. What will the temperature be when the pressure is raised to 4.0 atm at a constant volume. T1 P2 • P1V1T2 = P2V2T1 • (2.0atm)(X) = (4.0atm)(20+273) • 2X = 1172 • 586K