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Learn about the rules of evaluation in computer programming and how they differ from natural language. Understand the concepts of primitives, names, and application.
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Lecture 3: Rules of Evaluation David Evans http://www.cs.virginia.edu/evans CS200: Computer Science University of Virginia Computer Science
Menu • Language Elements • Why don’t we just program computers using English? • Evaluation • Procedures Scheduled Office Hours (Olsson 236A): Wednesdays 3:30-4:30 (after class) Thursdays 4:00-5:00 CS 200 Spring 2003
When learning a foreign language, which elements are hardest to learn? Primitives There are a lot of them, and learning the real meaning is hard Means of Combination Complex, but, all natural languages have similar ones (Chomsky) SOV (45% of all languages) (Korean): Sentence ::= Subject Object Verb SVO (42%): English: Sentence ::= SubjectVerbObject VSO (9%): Welsh: Sentence ::= Verb Subject Object “Lladdodd y ddraig y dyn.” (Killed the dragon the man.) OSV (<1%): Tobati (New Guinea) Schemish: Expression ::= (VerbObject) Means of Abstraction Few of these, but tricky to learn differences across languages Language Elements CS 200 Spring 2003
Core language issues list has 389 items! CS 200 Spring 2003
Why don’t we just program computers using English? CS 200 Spring 2003
Why don’t we just program computers using English? • Too hard and complex Non-native English speakers don’t need convincing. The rest of you have spent your whole life learning English (and first 5 years of your life doing little else) and still don’t know useful words like floccipoccinihilipilification! There are thoughts that even native speakers find it hard to express. By the end of today you will know enough Scheme (nearly the entire language) to express and understand every computation. By the end of the class, you will know enough to completely describe Scheme in terms of itself (try doing that in English!) CS 200 Spring 2003
Why don’t we just program computers using English? • Not concise enough English: To find the maximum of two numbers, compare them. If the first number is greater than the second number, return the first number. Otherwise, return the second number. Scheme: (define (max a b) (if (> a b) a b)) CS 200 Spring 2003
Why don’t we just program computers using English? • Limited means of abstraction There are only a few pronouns: he, she, it, they, these, … (English doesn’t even have a gender-neutral pronoun for a person!) Only Webster and Oxford can make up new ones. defineallows any programmer to make up as many pronouns as that programmer wants, and use them to represent exactly what the programmer wants. CS 200 Spring 2003
Why don’t we just program computers using English? • Mapping between surface forms and meanings are ambiguous and imprecise The 500 words used most in the English language each have an average of 23 different meanings in the Oxford English Dictionary. http://www.vuse.vanderbilt.edu/~jgray/funny.html I said he thought secret users only may write secret data.(From Only His Only Grammarian Can Only Say Only What Only He Only Means, Peter Neumann) The exact meaning(s) of every Scheme expression is determined by simple, unambiguous rules we will learn today (and refine later in the course). CS 200 Spring 2003
Expressions and Values • (Almost) every expression has a value • Have you seen any expressions that don’t have values? • When an expression with a value is evaluated, its value is produced CS 200 Spring 2003
Evaluation Rule 1: Primitives If the expression is a primitive, it is self-evaluating. > 2 2 > #t #t > + #<primitive:+> CS 200 Spring 2003
Evaluation Rule 2: Names If the expression is a name, it evaluates to the value associated with that name. > (define two 2) > two 2 CS 200 Spring 2003
Evaluation Rule 3: Application • If the expression is an application: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. (expression0 expression1 expression2 … ) CS 200 Spring 2003
Rules for Application • If the procedure to apply is a primitive, just do it. • If the procedure is a compound procedure, evaluate the body of the procedure with each formal parameter replaced by the corresponding actual argument expression value. CS 200 Spring 2003
Making Procedures • lambda means “make a procedure” Expression ::= (lambda(Parameters)Expression) Parameters ::= Parameters ::= Name Parameters CS 200 Spring 2003
Lambda Example: Tautology Function make a procedure with no parameters with body#t (lambda () #t) > ((lambda () #t) 200) #<procedure>: expects no arguments, given 1: 200 > ((lambda () #t)) #t > ((lambda (x) x) 200) 200 CS 200 Spring 2003
You’ve Already Used Lambda! (define (closer-color? sample color1 color2) Expr) is a shortcut for: (define closer-color? (lambda (sample color1 color2) Expr)) CS 200 Spring 2003
Eval and Apply are defined in terms of each other. Without Eval, there would be no Apply, Without Apply there would be no Eval! Eval Apply CS 200 Spring 2003
All of Scheme • Once you understand Eval and Apply, you can understand all Scheme programs! • Except: • We have special Eval rules for special forms (like if) Evaluation Rule 4: If it is a special form, do something special. CS 200 Spring 2003
Evaluating Special Forms • Eval 4-if. If the expression is (ifExpression0 Expression1 Expression2) evaluate Expression0. If it evaluates to #f, the value of the if expression is the value of Expression2. Otherwise, the value of the if expression is the value of Expression1. • Eval 4-lambda. Lambda expressions self-evaluate. (Do not do anything until it is applied.) CS 200 Spring 2003
More Special Forms • Eval 4-define. If the expression is (defineName Expression) associate the Expression with Name. • Eval 4-begin. If the expression is (beginExpression0 Expression1 …Expressionk) evaluate all the sub-expressions. The value of the begin expression is the value of Expressionk. CS 200 Spring 2003
Scheme Expression ::= Primitive Eval 1: If the expression is a primitive, it is self-evaluating. Expression ::= Name Eval 2: If the expression is a name, it evaluates to the value associated with that name.Expression ::= (ExpressionExpressionList)Eval 3: If the expression is an application:(a) Evaluate all the subexpressions (in any order)(b) Apply the value of the first subexpression to the values of all the other subexpressions. ExpressionList ::= ExpressionList ::=ExpressionExpressionList CS 200 Spring 2003
Special Forms Expression ::= (lambda (Parameters)Expression) Eval 4-lambda. Lambda expressions self-evaluate. Parameters ::= Parameters ::= NameParametersExpression ::= (defineNameExpression)Eval 4-define. If the expression is (defineName Expression) associate the Expression with Name. Expression ::= (ifExpression0 Expression1Expression2) Eval 4-if. Evaluate Expression0. If it evaluates to #f, the value of the if expression is the value of Expression2. Otherwise, the value of the if expression is the value of Expression1. Expression ::= (beginExpressionList Expression) Eval 4-begin. Evaluate all the sub-expressions. The value of the begin expression is the value of Expression. CS 200 Spring 2003
Now, you really know all of Scheme! (Except for 3 more special forms you will learn for PS5.) CS 200 Spring 2003
Example Evaluation (define square (lambda (x) (* x x))) (square 4) 16 CS 200 Spring 2003
A Squarish Example (define square (lambda (x) (* x x))) (square 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. CS 200 Spring 2003
(define square (lambda (x) (* x x))) (square 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. Evaluate: square It’s a name, use evaluation Rule 2: If the expression is a name, evaluate the expression associated with that name. (lambda (x) (* x x)) CS 200 Spring 2003
(define square (lambda (x) (* x x))) (square 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. Evaluate: square (lambda (x) (* x x)) Evaluate: 4 Rule 1: If the expression is a primitive, it is self-evaluating 4 CS 200 Spring 2003
(define square (lambda (x) (* x x))) (square 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. Apply: square (lambda (x) (* x x)) to 4 Application Rule 2. If the procedure is a compound procedure, evaluate the body of the procedure with each formal parameter replaced by the corresponding actual argument expression value. CS 200 Spring 2003
Apply: square (lambda (x) (* x x) ) to 4 Body of the procedure Application Rule 2. If the procedure is a compound procedure, evaluate the body of the procedure with each formal parameter replaced by the corresponding actual argument expression value. CS 200 Spring 2003
Apply: square (lambda (x) (* x x) ) to 4 Body of the procedure Application Rule 2. If the procedure is a compound procedure, evaluate the body of the procedure with each formal parameter replaced by the corresponding actual argument expression value. (* 4 4) CS 200 Spring 2003
Evaluate: (* 4 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. Evaluate: * Rule 1: If the expression is a primitive, it is self-evaluating <primitive:*> Evaluate: 4 Rule 1: If the expression is a primitive, … 4 Evaluate: 4 Rule 1: If the expression is a primitive, … 4 CS 200 Spring 2003
Evaluate: (* 4 4) Its an application, use evaluation Rule 3: • Evaluate all the subexpressions of the combination (in any order) • Apply the value of the first subexpression to the values of all the other subexpressions. Apply:<primitive:*> to 4 4 Application Rule 1: If the procedure to apply is a primitive, just do it. 16 CS 200 Spring 2003
(square 4) Eval Rule 3a: Application square 4 Eval Rule 1: Primitive Eval Rule 2: Names Eval Rule 3b: Application (lambda (x) (* x x)) 4 Apply Rule 2: Compound Application (* 44) Eval Rule 3a: Application 4 4 * Eval Rule 1: Primitive Eval Rule 1: Primitive 4 4 Eval Rule 3b: Application #<primitive:*> Apply Rule 1: Primitive Application 16 CS 200 Spring 2003
Charge • PS2 Due Monday 3 Feb • Less code to read than PS1, but now you should understand all of it! • Lots more code to write than PS1 • Reading for Friday: SICP, 1.2 • Reading for Monday: GEB, Ch 5 CS 200 Spring 2003