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This equation is true for all values of the variable. This is called an identity (many solutions).

This equation is true for all values of the variable. This is called an identity (many solutions). p. 98 3b. 6(y – 5) = 2(10 + 3y) 6y – 30 = 20 + 6y -6y -6y Subtract 6y on both sides -30  20 False (no solution) 39.

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This equation is true for all values of the variable. This is called an identity (many solutions).

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  1. This equation is true for all values of the variable. This is called an identity (many solutions). p. 98 3b. 6(y – 5) = 2(10 + 3y) 6y – 30 = 20 + 6y -6y -6y Subtract 6y on both sides -30  20 False (no solution) 39. Let d = the number of DVD’s they must sell to make a profit production cost = selling price 1500 + .80d = 1.59d - .80d = -.80d 1500 =.79d .79 .79

  2. d = 1898.7 The company must sell 1,899 DVD’s per day to make a profit. Let’s do 22.

  3. Geometry 22. Find the value of x so that the rectangles have the same area. A = lw A = 12x square units A = lw A = 16 (x – 2) A = 16x – 32 square units 12 units x – 2 units x units 16 units

  4. 12x = 16(x - 2) 12x = 16x - 32 -16x -16x_____ -4x = -32 -4 -4 x = 8 x needs to be 8 in order for the areas to be the same. A = lw A = 8(12) = 96 square units

  5. Example: 6v – 4 = v 8 2 (8) 6v – 4 = v (8) Multiply both sides by 8 8 2 6v – 4 = 4v -6v -6v Subtract 6v on both sides -4 = -2v -2 -2 Divide -2 on both sides 2 = v

  6. Now do 21. 21. 6(3a + 1) – 30 = 3(2a – 4) Exit Slip p. 97 Guided practice 1B under Example 1

  7. HW p. 100 10, 12, 16, 20

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