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First, write the equation. Count the number of atoms on each side of the equation. K - _____ Cl - _____ O - _____. K - _____ Cl - _____ O - _____. Count the number of atoms on each side of the equation. 1. K - _____ Cl - _____ O - _____. K - _____ Cl - _____ O - _____. 1. =. 1.
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Count the number of atoms on each side of the equation. K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____
Count the number of atoms on each side of the equation. 1 K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____ 1 = 1 1 = 3 2
Count the number of atoms on each side of the equation. 2x3=6 2 1 2 K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____ 1 = 1 2 1 = 3 6 2
Count the number of atoms on each side of the equation. 2 2 1 2 K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____ 1 2 = 1 2 1 2 = 3 6 2
Count the number of atoms on each side of the equation. 3x2=6 2 2 3 1 2 K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____ 1 2 = 1 2 1 2 = 3 6 2 6
Count the number of atoms on each side of the equation. 2 2 3 1 2 K - _____ Cl - _____ O - _____ K - _____ Cl - _____ O - _____ 1 2 = 1 2 1 2 = 3 6 2 6 =
To find the mass of the reactants: • Find each element on the Periodic Chart • Find the Atomic Mass for each element • Add the atomic mass for each atom to get the total mass for the reactants
78 K (potassium) has an atomic mass of 39. K (potassium) has an atomic mass of 39. There are 2 K (potassium) atoms. There are 2 K (potassium) atoms. 2x39= 78 2x39= 78
78 +70 Cl (chlorine) has an atomic mass of 35. There are 2 Cl (chlorine) atoms. 2x35= 70
78 +70 +96 2x3=6 O (oxygen) has an atomic mass of 16. There are 6 O (oxygen) atoms. 6x16= 96
78 +70 +96 =244
78 K (potassium) has an atomic mass of 39. There are 2 K (potassium) atoms. 2x39= 78
78 +70 =148 Cl (chlorine) has an atomic mass of 35. There are 2 Cl (chlorine) atoms. 2x35= 70
148 96 3x2=6 O (oxygen) has an atomic mass of 16. There are 6 O (oxygen) atoms. 6x16=96
148 96 148+96=244
244 244 YES