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First, write the equation. Count the number of atoms on each side of the equation. 1+2=3. Na - _____ H - _____ O - _____. 1. Na - _____ H - _____ O - _____. 1. 2. 3. 1. 1. Count the number of atoms on each side of the equation. 2X2=4. 2X1=2. 2. Na - _____ H - _____ O - _____.
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Count the number of atoms on each side of the equation. 1+2=3 Na - _____ H - _____ O - _____ 1 Na - _____ H - _____ O - _____ 1 2 3 1 1
Count the number of atoms on each side of the equation. 2X2=4 2X1=2 2 Na - _____ H - _____ O - _____ 1 Na - _____ H - _____ O - _____ 1 = 2 4 3 1 2 1 =
Count the number of atoms on each side of the equation. 2+2=4 2 2 2 Na - _____ H - _____ O - _____ 1 Na - _____ H - _____ O - _____ 1 = 2 4 3 4 1 2 1 2 =
Count the number of atoms on each side of the equation. 2 2 2 Na - _____ H - _____ O - _____ 1 = Na - _____ H - _____ O - _____ 1 2 4 3 4 = 1 2 1 2 =
Count the number of atoms on each side of the equation. 2 2 2 2 Na - _____ H - _____ O - _____ 1 2 = Na - _____ H - _____ O - _____ 1 2 4 3 4 = 1 2 1 2 =
To find the mass of the reactants: • Find each element on the Periodic Chart • Find the Atomic Mass for each element • Add the atomic mass for each atom to get the total mass for the reactants
46 Na (sodium) has an atomic mass of 23. There are 2 Na (sodium) atoms. 2x23= 46
2x2=4 46 4 H (hydrogen) has an atomic mass of 1. There are 4 H (hydrogen) atoms. 4x1-4
46 4 +32 2x16=32 O (oxygen) has an atomic mass of 16. There are 2 O (oxygen) atoms. 2x16=32
46 4 +32 46 + 4 +32 = 82
46 Na (sodium) has an atomic mass of 23. There are 2 Na (sodium) atoms. 2x23= 46
46 +32 O (oxygen) has an atomic mass of 16. There are 2 Na (sodium) atoms. 2x16= 32
46 +32 +2 H (hydrogen) has an atomic mass of 1. There are 2 H (hydrogen) atoms. 2x1= 2
46 +32 +2 +2 H (hydrogen) has an atomic mass of 1. There are 2 H (hydrogen) atoms. 2x1= 2
46 +32 +2 +2 46+32+2+2=82
82 82 YES