1 / 38

Basics of Linkage Analysis

Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions. Basics of Linkage Analysis. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions.

briar
Download Presentation

Basics of Linkage Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  2. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  3. Gene mapping problem Lähde: Morgan Genetics Tutorial. http://morgan.rutgers.edu/morganwebframes/level1/page2/karyotype.html

  4. One of the two main approaches in gene mapping. Uses pedigree data. Linkage Analysis

  5. Two loci are linked if they appear closeby in the same chromosome. The task of linkage analysis is to find markers that are linked to the hypothetical disease locus Complex diseases in focus  usually need to search for one gene at a time Requires mathematical modelling of meiosis Genetic linkage and linkage analysis

  6. Number of crossover sites is thought to follow Poisson distribution. Their locations are generally random and independent of each other. Meiosis and crossover

  7. The simple idea DIS Marker  • Recombination fraction  L( |data ) • Find • that maximises • Obtain measure for degree of evidence in favour of linkage (LOD score)

  8. Polymorphic loci whose locations are known Point mutations (SNP) or lengths of repetitive sequences Inherited together with the chromosomal segments Markersandinheritance 1 2 4 3 2 1 3 4 2 3 1 2 Father Mother 2 3 1 4 3 1 Child

  9. Two individuals share same allele label  they share the allele IBS (identical by state) Two individuals share an allele with same grandparental origin  they share an allele IBD (identical by descent) IBS sharing can easily be deduced from genotypes. IBD sharing provides more information. One can try to deduce IBD sharing based on family structure and inheritance. Markers and information

  10. Markers and information The children share allele 1 IBS. 1,2 2,3 They also share it IBD. 1,2 1,3

  11. Markers and information The children share allele 1 IBS. 1,2 1,3 They do not share alleles IBD. 1,2 1,3

  12. Markers and information The children share allele 1 IBS. 1,1 2,3 They either share or do not share it IBD. 1,2 1,3

  13. Chr. 1 1 2 1 12 1 2 1 1 2 1 1 5 2 14 1 3 2 1 2 2 Chr. 2 1 3 4 5 1 2 3 2 4 2 1 3 4 4 7 1 4 3 4 4 2 3 Chr. 22 2 1 1 3 2 2 2 3 3 4 Building blocks of linkage analysis Marker maps Pedigree structures Genotypes Phenotypes

  14. Information about disease model (in parametric analysis) Building blocks of linkage analysis  (aa), probability of a homozygote being affected  (Aa), probability of a heterozygote being affected  (AA), probability of a non-carrier being affected (phenocopy rate) • Information about environmental variables

  15. 13 0 0 5 0 0.0 0.0 0 1 2 3 4 5 6 7 8 9 10 11 12 13 1 2 0.99 0.01 1 0.001000 0.999000 0.999000 3 5 # M0 0.172 0.036 0.176 0.283 0.333 3 5 # M1 0.100 0.345 0.310 0.164 0.081 (---clip---) 3 5 # M10 0.169 0.432 0.147 0.130 0.122 3 5 # M11 0.397 0.204 0.151 0.043 0.205 0 0 0.10 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 1 0.1 0.45 1 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 3 1 2 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 4 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 5 1 2 1 1 3 1 2 1 4 5 1 6 3 2 3 3 5 4 2 5 4 3 2 5 3 2 4 5 1 6 0 0 2 2 4 4 3 4 2 5 9 7 1 7 1 3 2 5 5 3 4 6 2 5 2 1 2 1 1 7 0 0 1 1 5 1 2 2 5 2 6 6 5 1 1 3 3 2 5 5 3 4 5 5 4 4 2 1 1 8 1 2 2 1 3 3 2 2 4 5 6 6 3 5 1 4 5 4 1 5 4 3 2 5 3 2 4 5 1 9 3 4 1 1 3 4 2 2 5 2 6 6 5 5 4 1 4 5 5 3 3 6 2 5 2 3 2 1 1 10 3 4 2 1 3 4 2 5 4 3 1 6 3 2 1 3 5 5 2 3 4 2 4 5 4 3 5 1 1 11 5 6 1 1 1 4 1 4 5 5 6 7 2 7 3 3 5 5 2 3 4 6 2 5 3 1 4 1 1 12 5 6 2 2 3 4 2 4 4 5 1 7 3 7 3 3 5 5 2 3 4 6 5 5 2 1 5 1 1 13 5 6 1 2 3 4 1 4 5 5 6 7 2 7 3 3 5 5 2 3 4 6 2 5 3 1 5 1 1 14 7 8 1 1 5 3 2 2 2 5 6 6 5 5 1 4 3 4 5 5 3 3 5 5 4 2 2 5 1 15 7 8 2 1 1 3 2 2 2 5 6 6 5 5 1 4 3 4 5 5 3 3 5 2 4 3 2 4 1 16 0 0 1 1 5 5 2 4 5 6 3 1 1 1 3 4 4 4 3 7 1 3 5 4 3 2 1 4 1 17 16 12 1 2 5 4 2 4 5 5 3 7 1 7 3 3 4 5 7 3 3 6 4 5 2 1 4 5 1 18 16 12 2 1 5 3 4 2 6 4 1 1 1 3 3 3 4 5 3 2 1 6 4 5 2 1 4 1

  16. Example of linkage analysis results for one chromosome

  17. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  18. Parametric vs. non-parametric Dichotomous vs. continuous phenotypes Elston-Stewart vs. Lander-Green vs. heuristic Two-point vs. multipoint Genome scan vs. candidate gene Types of linkage analysis

  19. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  20. A common approach in statistical estimation Define hypotheses Generate likelihood function Estimate Test hypotheses Draw statistical conclusions Maximum likelihood estimation

  21. H0:  = 0.5 the disease locus isnot linked to the marker(s) HA:  0.5 the disease locus is linked to the marker(s) Hypotheses in linkage analysis

  22. Lj = gF P(gF) P(yF | gF)gM P(gM)P(yM | gM)gOi P(gOi | gF, gM) P(yOi | gO) The parameter  is incorporated here Likelihood function for a single nuclear family G = genotype probabilitiesy = phenotype probabilities

  23. The likelihood functions of multiple indpendent families are combined: L =  Lj or logL =  log Lj Several independent families

  24. Compute values of likelihood function under null and alternative hypotheses. Their relationship is expressed by LOD score (essentially derived from the likelihood ratio test statistic. Testing of hypotheses

  25. P-value gives a probability that a null hypothesis is rejected even though it was true. A LOD-score threshold of 3 corresponds to a single-test p-value of approximately 0.0001. In genome-wide gene mapping study, one conducts several (partially dependent) statistical tests. Applying the aforementioned threhold, the global p-value of 400 mutually independent test would be 1 - (1-0.0001)400 = 0.039  0.05. What if one focuses on individual candidate regions? On significance levels

  26. Single marker, dominant disease All genotypes known An example of ML estimation 1,3 2,4 2,3 1,4 1,2 1,4 1,2 3,4 1,2

  27. Paternal haplotype combinations Haplotype combinations of children, assuming unlinked loci

  28. 2,3 1,4 1,2 1,4 1,2 3,4 1,2 4 1 D 1 1- 1 + 3 +  1 D 0 3 D ½  1- 2 3 + 3 D 0 1- 3 + 2 ½  3 D 1 + 1 D 4  1- 1 + 1 1,3 2,4

  29. 0.56 0.5 LOD score 0.0 0.0 0.14 0.5 Recombination fraction LOD>3 taken as evidence of linkage.

  30. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  31. No assumption is made on disease model. The tests measure IBD sharing of alleles among affected relatives. ASP (Affected-Sib-Pair test) is the simplest form of NPL Requires nuclear families of two affected children Extendable to arbitrary pedigrees, missing data, and arbitrary group of affected relatives Idea of nonparametric linkage analysis

  32. Example analysis for one marker 3 4 3 4 1 2 1 2 2 4 1 3 1 3 2 3 1 3 2 3 3 4 3 4

  33. Collect large number of families with two affected offspring and deduce IBD status for each pair of offspring. Let us mark the number of sib-pairs with IBD status zero by n0. Respectively, n1 ja n2 are observed counts of the sib-pairs that share 1 or 2 alleles IBD. Compare the counts against the expected distribution by computing the value of the 2 test statistic. Idea of ASP test

  34. where e0 = 0.25n, e1 = 0.5n ja e2 = 0.25n. 2-test with 2 degrees of freedom. homozygous parents are a problem. lots of variants and implementations. Test statistic for ASP

  35. 1 1 7 1 1 1 1 1 1 1 1 1

  36. Idea of nonparametric linkage analysis Compare to the 2 cumulative distribution function (with 2 degrees of freedom): P=0.0012 The sample is too small for the 2 test to be reliable.

  37. Idea of Linkage Analysis Types of Linkage Analysis Parametric Linkage Analysis Nonparametric Linkage Analysis Conclusions Basics of Linkage Analysis

  38. Linkage analysis is a pedigree-based approach to gene mapping. Parametric vs. nonparametric methods. Hypothesis-driven vs. explorative analysis. Meta-analysis becoming increasingly popular. Conclusions

More Related