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An electric force of 4.5 x 10 -5 N is measured between two particles. One particle has a charge of 2.0 x 10 -6 C & the other has a charge of 3.0 x 10 -8 C. Calculate the distance between them. Chapter 21. Electric Fields.
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An electric force of4.5 x 10-5 N is measured between two particles. One particle has a charge of2.0 x 10-6 C & the other has a charge of 3.0 x 10-8 C. Calculate the distance between them.
Chapter 21 Electric Fields
Electric force like gravitational force is inversely proportioned to the square of the distance between the two points of concern
Electric Field (E) • A vector quantity that relates the force exerted on a charge to the amount of the charge
Electric Field (E) Fon q q E =
Electric Field (E) Fon q = qE
Calculate the electric field strength when a 25 N force is exerted on a charge of + 5.0 x 10-6 C
Typical Field Strengths Field Value (N/C) TV tube 1 x 105 Spark r 3 x 106 H orbital 5 x 1011
Electric Field Lines • Lines representing the force vectors in an electric field
Electric Field Lines • Always point from positive to negative
Electric Field Lines • Do not exist , but provide a model of a field
+ -
Electric Potential • The electric potential difference of charges measured in volts
Electric Potential • As with heat, we can only measure potential difference (DV)
Electric Potential Difference (DV) • The change in potential energy per unit charge
Electric Potential Difference (DV) • The work done moving a charge thru a field charge
Electric Potential Difference (DV) • Measured in J/C • J/C = volt (V)
Electric Potential Difference (DV) W on q q DV =
Electric Potential Difference (DV) DU = W
Electric Potential Difference (DV) DUq q DV =
Electric Potential Difference (DV) W on q q DV =
Electric Potential Difference (DV) W = Fd
Electric Potential Difference (DV) Fd on q q DV =
Electric Potential Difference (DV) F q DV = x d
Electric Potential Difference (DV) F q E =
Electric Potential Difference (DV) DV = Ed
Basic Equations • V = Ed • W = qV • F = qE
Equipotential • When the electric potential difference is 0
Equipotential • Charge rearranges itself to reach equipotential
Equipotential • When two spheres have the same charge, the larger one has lower electric potential
Equipotential • When two spheres have the same electric potential, the larger one has the greater charge
Equipotential • When a charged object comes in contact with a neutral one, the charge is • equally distributed
Equipotential • Because of the size of Earth, when objects touch Earth, their charge is passed to the Earth
Grounding • When a charged object touches Earth, all its charge flows to Earth creating equipotential
Electric Fields • All charges are on the outside of a conductor
Electric Fields • In pointed object, the field strength is greatest at the point
Capacitor • A device designed to store a charge
Capacitance • The ratio of charge to electric potential difference
Capacitance (C) q DV C =
Farad (F) • Unit for capacitance measured in coulombs per volt: F = C/V
Basic Equations • V = Ed • W = qV • F = qE • q = CV
A charge of 1.6 x 10-6 C is stored to create a capacitance of 4.0 x 10-3 F acting over 2.0 mm. Calculate: V, E, F, & W
A charge of 1.5 x 10-6 C is stored to create a capacitance of 4.0 x 10-3 F acting over 2.0 mm. Calculate: V, E, F, & W
A charge of 3.2 x 10-4 C is stored to create a capacitance of 8.0 mF acting over 4.0 mm. Calculate: V, E, F, & W
Charge =1.6 x 10-6 C Force = 3.2 x 10-3 N Distance = 64 nm. Calculate: V, E, C, & W
Calculate: 3.2 x 10-144x 1.5 x 10162 8.0 x 10-256 7.5 x 10175x 4.0 x 10122 =