1 / 34

Problems

Problems. Problems 3.75, 3.80, 3.87. 4. Random Variables. 4. Random Variables. Insurance companies have to take risks.

Download Presentation

Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Problems Problems 3.75, 3.80, 3.87

  2. 4. Random Variables

  3. 4. Random Variables Insurance companies have to take risks. When you buy insurance you are buying it in case something goes wrong. The insurance company is securing you and making money by betting that you are going to live a long life or that you are not going to crash your car.

  4. 4. Random Variables Insurance companies have to take risks. When you buy insurance you are buying it in case something goes wrong. The insurance company is securing you and making money by betting that you are going to live a long life or that you are not going to crash your car. It’s important that the insurance company offers it’s insurance at a fair price. How do they calculate it?

  5. 4. Random Variables It’s important that the insurance company offers it’s insurance at a fair price. How do they calculate it? Here is a simple model. An insurance company offers a death and disability policy which pay $10,000 when you die or $5000 if you are disabled. The company charges $50/year for this benefit. Should the company expect a profit?

  6. 4. Random Variables Here is a simple model. An insurance company offers a death and disability policy which pay $10,000 when you die or $5000 if you are disabled. The company charges $50/year for this benefit. Should the company expect a profit? We need to define some terms first.

  7. 4. Random Variables A random variable is a way of recording a numerical result of a random experiment. Each sample point is given one numerical value.

  8. 4. Random Variables A random variable is a way of recording a numerical result of a random experiment. Each sample point is given one numerical value. In this case the random variable is the payout of the insurance company.

  9. 4. Random Variables A random variable is a way of recording a numerical result of a random experiment. Each sample point is given one numerical value. In this case the random variable is the payout of the insurance company. We usually use capital X to represent our random variable.

  10. 4. Random Variables In this case the random variable is the payout of the insurance company. We usually use capital X to represent our random variable.

  11. 4. Random Variables Now we need to know what happens.

  12. 4. Random Variables Now we need to know what happens. The insurance company uses actuaries to determine the probability of certain events occurring.

  13. 4. Random Variables The probability the insurance company will have to pay $10,000 is 1 in a thousand is represented with:

  14. 4. Random Variables The probability the insurance company will have to pay $5,000 is 2 in a thousand is represented with:

  15. 4. Random Variables In this case the random variable is the payout of the insurance company. We usually use capital X to represent our random variable.

  16. 4. Random Variables In this case the random variable is the payout of the insurance company. We usually use capital X to represent our random variable.

  17. 4. Random Variable This is called a probability distribution table.

  18. 4. Random Variable This is called a probability distribution table. We may draw the distribution (on a histogram)

  19. Discrete vs ContinuousRandom Variables The random variable in the previous example is called a discrete random variable, since X takes an one of a specific number of values A continuous random variable is one that can take on a range of values inside of an interval. (Example: X represents the height of a randomly selected individual).

  20. 4. Random Variable Should the company earn be selling these policies?

  21. Expected value Mean or expected value of a discrete random variable is: µ = E(x) = ∑ x P (x)

  22. Expected value Mean or expected value of a discrete random variable is: µ = E(x) = ∑ x P (x) The standard deviation of a discrete random variable is given by

  23. In planning a huge outdoor concert for June 16, the producer estimates the attendance will depend on the weather according to the following table. She also finds out from the local weather office what the weather has been like, for June days in the past 10 years. Weather Attendance Relative Frequency wet, cold 5,000 .20 wet, warm 20,000 .20 dry, cold 30,000 .10 dry, warm 50,000 .50 What is the expected (mean) attendance? The tickets will sell for $9 each. The costs will be $2 per person for the cleaning and crowd-control, plus $150,000 for the band, plus $60,000 for administration (including the facilities). Would you advise the producer to go ahead with the concert, or not? Why? Example: Concert Planning

  24. Properties of Probability, P( X = xi )

  25. Example The random variable x has the following discrete probability distribution: Find P (x≤17) P (x =19) P (x≥17) P(x≤19) P (x <16 or x >17)

  26. Example The random variable x has the following discrete probability distribution: Find P (X≤17)= .7 P (X =19)= .2 P (X≥17) =.3 P(X≤19)= 1 P (X <16 or X >17)= .5

  27. Example The random variable x has the following discrete probability distribution: Find: The expect value and standard deviation of this random variable.

  28. Example The random variable x has the following discrete probability distribution: Find: The expect value and standard deviation of this random variable. µ = E(X)=16.8

  29. Example The random variable x has the following discrete probability distribution: Find: The expect value and standard deviation of this random variable. µ = E(X)=16.8 and

  30. Example The random variable x has the following discrete probability distribution: Find: The expect value and standard deviation of this random variable. µ = E(X)=16.8 and

  31. Empirical Rule and Chebyshev’s Rule Chebyshev’s Rule and the Empirical Rule for Random Variables. That is 1) The number of points that fall within k standard deviation of the mean is at least: 1-1/k2. 2) If the distribution of the Random Variable is a normal bell shaped curve, 68% of data points are in , 95% are in and 99.7% are in

  32. Descriptive Phrases Descriptive Phrases require special care! • At most • At least • No more than • No less than

  33. Problems Problems 4.12, 4.17, 4.36, 4.40, 4.43

  34. Homework • Review Chapter 3, 4.1-4.3 • Read Chapter 4.4, 5.1-5.3 • Have a great Thanksgiving

More Related