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293 g

THANKSGIVING H.W. ANSWERS. (. ). 150.0 g. 1 mol. (. ). 1. 293 g. K 2 Cr 2 O 7. 1a) Molar mass (GFM) = 293.992 g/mol. 1b) 2 moles of K are in I mole of. K 2 Cr 2 O 7. 1c)How many moles are in the 150.00 grams of. =0.5102mol K 2 Cr 2 O 7. K 2 Cr 2 O 7.

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293 g

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  1. THANKSGIVING H.W. ANSWERS ( ) 150.0 g 1 mol ( ) 1 293 g K2Cr2O7 1a) Molar mass (GFM) = 293.992 g/mol 1b) 2 moles of K are in I mole of K2Cr2O7 1c)How many moles are in the 150.00 grams of =0.5102mol K2Cr2O7 K2Cr2O7

  2. 1c) How many particles are in the 150.00 g ( ) 6.02 x 1023 particles 150.0 g 1 mol ( ( ( ) ) ) 1 293 g 1 mol = 3.07 x 1023 molecules K2Cr2O7 1d) What is the mass of 12.04 x 1023 particles of K2Cr2O7 ( ) ( ) 12.01 x 1023 particles 1 mol 293 g = 3.07 x 1023 molecules K2Cr2O7 1 6.02 x 1023 particles 1 mol

  3. 2a-b)what is the mass of 18.06 x 1023 particles of NH3(gfm=17g/mol) ( ) ( ) 18.06 x 1023 particles 1 ( ) ( ) ( ) 18.06 x 1023 PARTICLES 1 mol 17 g 51.0 g NH3 1 6.02 x 1023 PARTICLES 1 mol 2c) What is the mass of 12.04 x 1023 particles of K2Cr2O7 ( ) 1 mol 22.4L =67.2 L NH3 6.02 x 1023 particles 1 mol

  4. 3)How many grams of lead nitrate = the moles of 150.00 grams of K2Cr2O7 ? ( ) 150.0 g 1 mol ( ) 1 293 g =0.5102 mol K2Cr2O7 ( ) ( ) 331.152 g 0.5102mol 168.954 g= Pb(NO3)2 1 1 mol Pb(NO3)2 Molar mass (GFM) = 331.152 g/mol

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