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BCOR 1020 Business Statistics. Lecture 17 – March 18, 2008. Overview. Chapter 8 – Sampling Distributions and Estimation Confidence Intervals Mean ( m ) with variance ( s ) unknown Sample size determination for the mean ( m ). Chapter 8 – Confidence Interval for a Mean ( m ) with Unknown s.
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BCOR 1020Business Statistics Lecture 17 – March 18, 2008
Overview • Chapter 8 – Sampling Distributions and Estimation • Confidence Intervals • Mean(m) with variance (s) unknown • Sample size determination for the mean (m)
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Suppose we want to find a confidence interval for m when s is unknown: • Instead of using • We will estimate s with S and use We need to know how this statistic distributed to compute the confidence interval for m when s is unknown?
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s has a Student’s t distribution with (n – 1) degrees of freedom, denoted T ~ t(n–1). • Assumes the population from which we are sampling is Normal. • t distributions are symmetric and shaped like the standard normal distribution. • The t distribution is dependent on the size of the sample. (As n increases, the t distribution approaches the standard normal.)
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Degrees of Freedom: • Degrees of Freedom (d.f.) is a parameter based on the sample size that is used to determine the value of the t statistic. • Degrees of freedom (denoted by n) tell how many independent observations are used to calculate our estimate of s, S. n = n - 1 • For a given confidence level, t is always larger than z, so a confidence interval based on t is always wider than if z were used.
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Comparison of z and t: • For very small samples, t-values differ substantially from the normal. • As degrees of freedom increase, the t-values approach the normal z-values. • For example, for n = 31, the degrees of freedom are: • What would the t-value be for a 90% confidence interval? n = 31 – 1 = 30
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Comparison of z and t: • For n = 30, the corresponding t-value is 1.697. • Compare this to the 90% z-value, 1.645.
Clickers Use the table below to find the t-value for a 95% confidence interval from a sample of size n = 6. A = 3.365 B = 2.015 C = 1.960 D = 2.571
sn x+ta Chapter 8 – Confidence Interval for a Mean (m) with Unknown s • Use the Student’s t distribution instead of the normal distribution when the population is normal but the standard deviation s is unknown and the sample size is small. Constructing the Confidence Interval with the Student’s t Distribution: • Solving the inequality inside the probability statement • P(–ta < < ta) = 1 – a leads to the interval • The confidence interval for m (unknown s) is
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Graphically…
x = 510 s = 73.77 Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Example: GMAT Scores • Here are GMAT scores from 20 applicants to an MBA program: • Construct a 90% confidence interval for the mean GMAT score of all MBA applicants. • Since s is unknown, use the Student’s t for the confidence interval with n = 20 – 1 = 19 d.f. • First find t0.90 from Appendix D.
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Example: GMAT Scores For n = 20 – 1 = 19 d.f., t0.90 = 1.729 (from Appendix D).
sn sn x - t x + t 510 + 28.52 < m < 510 – 28.52 73.77 20 73.77 20 510 – 1.729 510 + 1.729 < m < < m < Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Example: GMAT Scores • The 90% confidence interval is: • We are 90% certain that the true mean GMAT score is within the interval 481.48 < m < 538.52.
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Using Appendix D: • Beyond n = 50, Appendix D shows n in steps of 5 or 10. • If the table does not give the exact degrees of freedom, use the t-value for the next lower n. • This is a conservative procedure since it causes the interval to be slightly wider. Using MegaStat: • MegaStat gives you a choice of z or t and does all calculations for you.
Clickers A sample of 20 final exams from BCOR1020 has an average of and a standard deviation of S = 8. Assuming the population of final exam scores is normally distributed, find the appropriate t distribution critical value to determine the 95% confidence interval for the mean score. (t-dist. Table on overhead) A) t = 1.725 B) t = 1.729 C) t = 2.086 D) t = 2.093
Clickers A sample of 20 final exams from BCOR1020 has an average of and a standard deviation of S = 8. Assuming the population of final exam scores is normally distributed, find the 95% confidence interval for the mean score. (t-dist. Table on overhead) A) B) C) D)
Chapter 8 – Confidence Interval for a Mean (m) with Unknown s Confidence Interval Width: • Confidence interval width reflects - the sample size, - the confidence level and - the standard deviation. • To obtain a narrower interval and more precision- increase the samplesize or - lower the confidence level (e.g., from 90% to 80% confidence)
Chapter 8 – Sample Size Determination for C. I. for a Mean (m) • To estimate a population mean with a precision of +E (allowable error), you would need a sample of what size? Sample Size to Estimate m(assuming s is known): • This formula is derived by comparing the intervals m+E and m+ . • Solving the following equation for n: • Gives us the formula: Always round up!
Method 1: Take a Preliminary Sample: Take a small preliminary sample and use the sample s in place of s in the sample size formula. Method 2: Assume Uniform Population: Estimate rough upper and lower limits a and b and set s = [(b-a)/12]½. Method 3: Assume Normal Population: Estimate rough upper and lower limits a and b and set s = (b-a)/4. This assumes normality with most of the data with m+ 2s so the range is 4s. Method 4: Poisson Arrivals: In the special case when m = l is a Poisson arrival rate, then s = m = l . Chapter 8 – Sample Size Determination for C. I. for a Mean (m) How to Estimate an unknown s?
Chapter 8 – Sample Size Determination for C. I. for a Mean (m) Example: GMAT Scores • Recall from our last lecture that the population standard deviation for GMAT scores is s = 86.8. • How large should our sample be if we would like to have a 95% confidence interval for average GMAT scores that is no wider than + 20 points? • We know • s = 86.8, E = 20, z = 1.96 for 95% C.I. • So, • Since we always round up, we will draw a sample of size n = 73.
Clickers Suppose we want to find a confidence interval for the mean score on BCOR1020 final exams. Assuming the population of final exam has a standard deviation of s = 8, how large should our sample be if we would like a 95% confidence interval no wider than + 2 points? A) n = 30 B) n = 62 C) n = 100 D) n = 246