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The Islamic University of Gaza Faculty of Engineering Civil Engineering Department Hydraulics - ECIV 3322. Open Channel. Chapter 6. Example 1. Open channel of width = 3m as shown, bed slope = 1:5000, d=1.5m find the flow rate using Manning equation, n=0.025. Example 2.
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The Islamic University of GazaFaculty of EngineeringCivil Engineering DepartmentHydraulics - ECIV 3322 Open Channel Chapter 6
Example 1 Open channel of width = 3m as shown, bed slope = 1:5000, d=1.5m find the flow rate using Manning equation, n=0.025.
Example 2 Open channel as shown, bed slope = 69:1584, find the flow rate using Chezy equation, C=35.
Example 3 Circular open channel as shown d=1.68m, bed slope = 1:5000, find the Max. flow rate & the Max. velocity using Chezy equation, C=70. Max. flow rate
Example 4 Trapezoidal open channel as shown Q=10m3/s, velocity =1.5m/s, for most economic section. find wetted parameter, and the bed slope n=0.014.
Example 5 Determine the critical depth if the flow is 1.33m3/s. the channel width is 2.4m
Example 6 Rectangular channel , Q=25m3/s, bed slope =0.006, determine the channel width with critical flow using manning n=0.016
Example 7 A 3-m wide rectangular channel carries 15 m3/s of water at a 0.7 m depth before entering a jump. Compute the downstrem water depth and the critical depth
d2 d1=dn Example 8 dn = Depth can calculated from manning equation
d2 d1=dn a) b)
d2 d1=dn c)
Example 9 A trapezoidal channel with a bottom width of 5m, side slope of 1H: 1V, and a Manning n of 0.013 carries a discharge of 50m3/s at a slope of 0.0004. Compute by the direct step method the backwater profile created by a dam that backs up the water to a depth of 6 m immediately behind the dam. The upstream end of the profile is assumed at a depth equal to 1% greater than the normal depth.
determine normal depth, Yn By trial and error, Yn = 2.87 m
determine critical depth, Yc By trial and error, Yc = 1.90 m Control depth = 1.01*2.87 =2.90m