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CUBE and CUBOID

CUBE and CUBOID. To calculate the volume and surface area of cube and cuboid. Created by Cep Andi Alim Subarkah for mathlabsky.wordpress.com. Created by Cep Andi Alim Subarkah for mathlabsky.wordpress.com. CUBE. H. G. F. E. r cm. D. C. r cm. A. B. r cm.

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CUBE and CUBOID

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  1. CUBE and CUBOID To calculate the volume and surface area of cube and cuboid Created by CepAndiAlimSubarkah for mathlabsky.wordpress.com Created by CepAndiAlimSubarkah for mathlabsky.wordpress.com

  2. CUBE H G F E r cm D C r cm A B r cm Example 1 Example 2 Example 3 3

  3. Given the measure edges of a cube is 5cm. Calculate a. The length of diagonal c. The surface area b. The volume Answer: a. L.O.D = r = 5 = = = 8 cm b. Vol = = = = 125 cm3 c. S. A = = = = cm2

  4. Given a cube has length of face diagonal is cm. Calculate a. The volume b. The surface area Answer: L.O.F.D = cm = = : = = 6cm a. Vol= = = = 216 cm3 b. S. A= = = = 216 cm2

  5. Given a cube has surface area is 150cm2 . Calculate a. The length of face diagonal b. The Volume Answer: S. A = 150 cm2 = 150 = 150 : 6 = 25 = = cm a. L.OF.D= = = = cm b. Vol = = = = cm3

  6. CUBOID G H F E h cm D C ) w cm A B l cm Example 1 Example 2 Example 3

  7. Given a cuboid has measurement 6cm x 4cm x 7cm. Calculate: a. Length of diagonal c. The volume b. The surface area Answer: b. S.A = 2(l.w + l.h + w.h) = 2(6x4 + 6x7 + 4x7) = 2(24 + 42 + 28) = 2(94) = 118 cm2 a. L.O.D = = = = c. Vol = l x w x h = 6 x 4 x 7 = 168 cm3

  8. Given a cuboid has measure edges of based is 5cm x 4cm, and the sum of edges is 68 cm. Calculate: a. The volume b. The surface area Answer: a. Vol= l x w x h = 5 x 4 x 8 = 160 cm3 S.O.E = 68 cm 4 (l + w + h) = 68 4 (5 + 4 + h) = 68 4 (9 + h) = 68 9 + h = 68 : 4 = 17 h = 17 – 9 = 8 cm b. S.A= 2(l.w + l.h + w.h) = 2(5x4 + 5x8 + 4x 8) = 2(20 + 40 + 32) = 2 (92) = 184 cm2

  9. Given a cuboid has measure edges of based is 5cm x 8cm, and the surface area is 184cm2. Calculate: a. The volume b. The length of diagonal a. Vol = l x w x h = 5 x 8 x 4 = 160 cm3 Answer: The Surface Area = 184 2(l.w + l.h + w.h) = 184 2(5x8 + 5xh + 8xh) = 184 40 + 5h + 8h = 184 : 2 = 92 13h = 92 – 40 = 52 h = 52 : 13 = 4 cm b. L,O,D = = = = cm

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