310 likes | 440 Views
CS 261 - Spring 2008. Skip Lists. Skip Lists Advantages. Ordinary linked lists and arrays have fast (O(1)) addition, but slow search Sorted Vectors have fast search (O(log n)) but slow insertion Skip Lists have it all - fast (O(log n)) addition, search and removal times!
E N D
CS 261 - Spring 2008 Skip Lists
Skip Lists Advantages • Ordinary linked lists and arrays have fast (O(1)) addition, but slow search • Sorted Vectors have fast search (O(log n)) but slow insertion • Skip Lists have it all - fast (O(log n)) addition, search and removal times! • Cost - Slightly more complicated
Start with an ordered listLets begin with a simple ordered list, sentinel on the left, single links.
Start of the struct definition struct skiplist { struct skiplink * sentinel; int size; };
Operations • Add (Object newValue) - find correct location, add the value • Contains (Object testValue) - find correct location, see if its what we want • Remove (Object testValue) - find correct location, possibly remove it • See anything in common?
Slide Right struct skiplink * slideRight (struct skiplink * current, EleType testValue) { while ((current->next != 0) && LT(current->next->value, testValue)) current = current->next; return current; } Finds the link RIGHT BEFORE the place the value we want should be, if it is there
Add (EleType newValue) void add (struct skiplist* lst, EleType newValue) { struct skiplink * current = slideRight(lst->sentinel, newValue); struct link * newLink = (struct link *) malloc(sizeof(struct link)); assert (newLink != 0); newLink->value = newValue; newLink->next = current->next; current->next = newLink; lst->size++; }
Contains (EleType testValue) int contains (struct skip *lst, EleType testValue) { struct skiplink * current = slideRight (lst->leftSentinel, testValue); if ((current->next != 0) && (EQ(testValue, current->next->value))) return true; return false; } /* reminder, this is one level list, not real skiplist */
Remove (Object testValue) void remove (struct skiplist *lst, EleType testValue) { struct skiplink * current = slideRight (lst->leftSentinel, testValue); if ((current->next != 0) && (EQ(testValue, current->next->value))) { current->next = current->next->next; free(current->next); lst->size--; } }
Problem with Sorted List • What’s the use? • Add is still O(n), so is contains, so is remove. • No better than an ordinary list. • Major problem with list - sequential access
Why no binary search?What if we kept a link to middle of list?
In theory it would work….. • In theory this would work • Would give us nice O(log n) search • But would be really hard to maintain as values were inserted and removed • What about if we relax the rules, and don’t try to be so precise…..
The power of probability • Instead of being precise, keep a hierarchy of ordered lists with downward pointers • Each list has approximately half the elements of the one below • So, if the bottom list has n elements, how many levels are there??
Contains (Object testValue) • Starting at topmost sentinel, slide right • If next value is it, return true • If next value is not what we are looking for, move down and slide right • If we get to bottom without finding it, return false
Notes about contains • See how it makes a zig-zag from top to bottom • On average, slide only moves one or two positions • So basically proportional to height of structure • Which is????? O( ?? )
Remove Algorithm • Start at topmost sentinal • Loop as follows • Slide right. If next element is the one we want, remove it • If no down element, reduce size • Move down
Notice about Remove • Only want to decrement size counter if at bottom level • Again, makes zig-zag motion to bottom, is proportional to height • So it is again O(log n)
Add (Object newElement) • Now we come to addition - the most complex operation. • Intuitive idea - add to bottom row (remember to increment count) • Move upwards, flipping a coin • As long as heads, add to next higher row • At top, again flip, if heads make new row
Add ExampleInsert the following: 9 14 7 3 20Coin toss: T H T H H T H T (insert if heads)
The Power of Chance • At each step we flip a coin • So the exact structure is not predictable, and will be different even if you add the same elements in same order over again • But the gross structure is predictable, because if you flip a coin N times as N gets large you expect N/2 to be heads.
Notes on Add • Again proportional to height of structure, not number of nodes in list • So also O(log n) • So all three operations are O(log n) ! • By far the fastest overall Bag structure we have seen! • (Downside - does use a lot of memory as values are repeated. But who cares about memory? )
int skipListContains(struct skipList* slst, EleType d) { struct skipLink *tmp = slst->topSentinel; while (tmp != 0) { tmp = slideRight(tmp, d); if ((tmp->next != 0) && EQ(d, tmp->next->value)) return 1; tmp = tmp->down; } return 0; }
void skipListAdd(struct skipList * slst, EleType d) { struct skipLink *downLink, *newLink; downLink = skipLinkAdd(slideRight(slst->topSentinel,d),d); if (downLink != 0 && skipFlip()) { newLink = newSkipLink(d, 0, downLink); slst->topSentinel = newSkipLink(0, newLink, slst->topSentinel); } slst->size++; }
struct skipLink* skipLinkAdd(struct skipLink * current, EleType d) { struct skipLink *newLink, *downLink; newLink = 0; if (current->down == 0) { newLink = newSkipLink(d, current->next, 0); current->next = newLink; } else { downLink = skipLinkAdd(slideRight(current->down, d), d); if (downLink != 0 && skipFlip()) { newLink = newSkipLink(d, current->next, downLink); current->next = newLink; } } return newLink; }
struct skipLink* newSkipLink(EleType d, struct skipLink * nlnk, struct skipLink* dlnk) { struct skipLink * tmp = (struct skipLink *) malloc(sizeof(struct skipLink)); assert(tmp != 0); tmp->value = d; tmp->next = nlnk; tmp->down = dlnk; return tmp; }
void skipListRemove(struct skipList* slst, EleType d) { struct skipLink *current, *tmp; current = slst->topSentinel; while (current != 0) { current = slideRight(current, d); if (current->next != 0 && EQ(d, current->next->value)) { tmp = current->next; current->next = current->next->next; free(tmp); if (current->down != 0) slst->size--; } current = current->down; } }