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Tuesday, Feb 25

Tuesday, Feb 25. Chapter 10 Review. Chapter 10 Review. Find the area of the Base. Round to the nearest tenth, if necessary. . Chapter 10 Review. What is the area of the Base? Round to the nearest tenth, if necessary. B = 9.1 x 8 = 72.8in². Chapter 10 Review.

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Tuesday, Feb 25

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  1. Tuesday, Feb 25 Chapter 10 Review

  2. Chapter 10 Review Find the area of the Base. Round to the nearest tenth, if necessary.

  3. Chapter 10 Review What is the area of the Base? Round to the nearest tenth, if necessary. B = 9.1 x 8 = 72.8in²

  4. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary.

  5. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary. V = lwh V = 9.1x 8 x 8 = 582.4in³ or V = Bh = 72.8 · 8 = 582.4in³

  6. Chapter 10 Review Find the area of the Base. Round to the nearest tenth, if necessary.

  7. Chapter 10 Review Find the area of the Base. Round to the nearest tenth, if necessary. B = 18 x 9 = 162mm²

  8. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary.

  9. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary. V = lwh V = 18 x 9 x 36 = 5832mm³ or V = Bh = 162 · 36 = 5832mm³

  10. Chapter 10 Review Find the area of the Base. Round to the nearest tenth, if necessary.

  11. Chapter 10 Review Find the area of the Base. Round to the nearest tenth, if necessary. B = 10 x 6 ÷ 2 = 30cm²

  12. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary.

  13. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary. V = lwh ÷ 2 V = 10 x 6 x 4 ÷ 2 = 120cm³ or V = Bh = 30 · 4 = 120cm³

  14. Chapter 10 Review Find the Area of the Base. Round to the nearest tenth, if necessary.

  15. Chapter 10 Review Find the Area of the Base. Round to the nearest tenth, if necessary. B = 3 x 4 ÷ 2 = 6cm²

  16. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary.

  17. Chapter 10 Review Find the volume. Round to the nearest tenth, if necessary. V = lwh ÷ 2 V = 4x 3 x 8 ÷ 2 = 48cm³ or V = Bh = 6 · 8 = 48cm³

  18. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary.

  19. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary. A = 7 x 4 = 28 A = 4 x 10 = 40 A = 10 x 7 = 70 28 + 28 + 40 + 40 + 70 + 70 =276in²

  20. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary.

  21. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary. SA = 2B + hp B = 72.8 h = 8 p = 34.2 SA = 2 x 72.8 + 8 x 34.2 = = 145.6 + 273.6 = 419.2in²

  22. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary.

  23. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary. SA = 2B + hp B = 162 h= 36 p = 54 SA = 2 x 162 + 36 x 54 = = 324 + 1944 = 2268mm²

  24. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary.

  25. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary. SA = 2B + hp B = 3 x 4 ÷ 2 = 6 h= 8 p = 12 SA = 2 x 6 + 8 x 12 = = 12 + 96 = 108cm²

  26. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary.

  27. Chapter 10 Review Find the surface area. Round to the nearest tenth, if necessary. SA = 2B + hp B = 10 x 6 ÷ 2 = 30 h= 4 p = 25.6 SA = 2 x 30 + 4 x 25.6 = = 60 + 102.4 = 162.4cm²

  28. Chapter 10 Review A special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box?

  29. Chapter 10 Review A special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box? V = lwh ÷ 2 V = 8x 7.1 x 6.9 ÷ 2 = 195.96in³

  30. Chapter 10 Review There is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy?

  31. Chapter 10 Review There is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy? V = lwh V₁ = 5 x 6 x 9= 270in³ V₂ = 4 x 8 x 8 = 256in³

  32. Chapter 10 Review You are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft². How many gallons will you need?

  33. Chapter 10 Review You are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft². How many gallons will you need? SA = 2B + hp B = 20 · 35 = 700 h = 10 p = 20+35+20+35=110 SA = 2 x 700 + 110 x 10 = 2500ft² 2500 ÷ 1250 = 2 gallons

  34. Chapter 10 Review Formulas you will need to have memorized for tomorrow: Volume of a rectangular prism V = lwh and V = Bh Volume of a triangular prism V = lwh ÷ 2 and V = Bh Surface Area of a prism SA = 2B + hp

  35. Chapter 10 Review Agenda Notes Homework – Chapter 10 Review Homework- (extra credit for 4th period) Due Wednesday, Feb 26 Chapter 10 Test - Wednesday, Feb 26

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