300 likes | 453 Views
Check your homework assignment with your partner!. 1. WARM UP EXERCSE. B. Q. 20. 12. P. R. A. 16. C. ∆ABC with sides 12, 16, 20 is circumscribed about a circle with points of tangency P, Q, R. Find the radius of the circle. WARM UP EXERCSE. B. Q. 20. 12. P. R. A. 16. C.
E N D
WARM UP EXERCSE B Q 20 12 P R A 16 C ∆ABC with sides 12, 16, 20 is circumscribed about a circle with points of tangency P, Q, R. Find the radius of the circle.
WARM UP EXERCSE B Q 20 12 P R A 16 C ∆ABC with sides 12, 16, 20 is circumscribed about a circle with points of tangency P, Q, R. Find the radius of the circle. Hint: it is a right triangle! 20 - x x
§10.1 Circles The student will learn: More about of circles and the lines associated with them. 4
The lines were are going to consider are tangent lines, and secant lines which contain chords of the circle. We will begin our study with parallel lines. That is, lines which do not intersect. Most of the theorems will use information from the last class and not triangles. Parallel Lines and Circles 5
Parallel Lines and Circles Theorem: Parallel lines intercept equal arcs on a circle. C D C D C D B A A B A B There are three cases: a tangent and a secant, two secants, and two tangents. 6
Tangent-Secant Proof O P D C A B E Given: AB ‖ CD and AB tangent at E. Prove: arc CE = arc DE Think! The other cases can be reduced to this case. 7
We will now move on to non-parallel lines. These line (tangents & secants) may intersect on the circle, or inside the circle or outside the circle. Non Parallel Lines and Circles Let’s begin with the case where the lines intersect on the circle. 8
Inscribed Angles (SS on C) Angle ABC is an inscribed angle of a circle if AB and BC are chords of the circle. A A A O O O B B B C C C Theorem: If an angle is inscribed in a circle, then its measure is half the measure of its intercepted arc. There are three cases: 9
Proof A Given: Inscribed angle ABC. Prove: ABC= ½ arc AC Case 1: O on angle. O B C Note: This theorem implies that an angle inscribed in a semicircle is a right angle. 10
Theorem (ST on C) An angle formed by a chord and a tangent at one end of the chord is half the intercepted arc. D C B A 11
Proof D C B A Given: Chord AC, tangent AB Prove: CAB= ½ arc AC 12
Non Parallel Lines and Circles There is no case of two tangents intersecting on the circle. 13
Non Parallel Lines and Circles We now move to the cases where the lines meet inside the circle. 14
Theorem An angle formed by two intersecting chords is half the sum of the two intercepted arcs. C E B A D 15
Proof C E B A D Given: Chords AB and CD met at E. Prove AEC = ½ (arc AC + arc BD) 16
Non Parallel Lines and Circles There is no cases involving tangents meeting inside of the circle. 17
Non Parallel Lines and Circles And finally to the cases where the lines meet outside the circle. 18
Theorem An angle formed by two secants, by a secant and tangent, or by two tangents is half the difference of the intercepted arcs. 19
Two Secant Proof A D B Given: Secants AB & CB. Prove: B = ½ arc AC - ½ arc DE E C 20
We will now move into an area of geometry sometimes called “Power Theorems”. We will be dealing with three theorems that involve tangents, chords and secants and the measurement of segments of these figures. We will need the properties of similar triangles for this. A future lesson!! 21
The Two-Secant Power Theorem. Given a circle C, and a point Q of its exterior. Let L 1 be a secant line through Q, intersecting C in points R and S; and let L 2 be another secant line through Q, intersecting C in points U and T. Then QR · QS = QU · QT S R Q U T 22
Two Secant Power Theorem: QR · QS = QU · QT (4) S R Q U T What will we prove? Given: Drawing What is given? Prove: QR · QS = QU · QT (1) Q = Q Reflexive Why? (2) QSU = QTR Intercept same arcs. Why? (3) QSU ~ QTR Why? AA. Why? Property similar s. Why? Arithmetic. (5) QR · QS = QU · QT QED 23
The Tangent - Secant Power Theorem. Given a tangent segment QT to a circle, and a secant line through Q, intersecting the circle in points R and S. Then QR · QS = QT 2 S R Q T 24
The Tangent - Secant Power Theorem. S R Q T Given: Drawing What is given? What will we prove? Prove: QR · QS = QT 2 For Homework. Prove QST ~ QTR and set up the appropriate proportion to cross multiply to get QR · QS = QT 2 25
The Two-Chord Power Theorem. Let RS and TU be chords of the same circle, intersecting at Q. Then QR · QS = QU · QT S Q T U R 26
The Two-Chord Power Theorem. S Q T U R Given: Drawing What is given? Prove: QR · QS = QU · QT What will we prove? For Homework. Prove SQU ~ TQR and set up the appropriate proportion to cross multiply to get QR · QS = QU · QT. 27
The Two-Chord Power Theorem. What is given? What will we prove? Given: Prove: (1) Statement 1 Why? Reason 1. (2) Statement 2 Why? Reason 2. (3) Statement 3 Reason 3. Why? (4) Statement 4 Why? Reason 4. (5) Statement 5 Reason 5. Why? (6) Statement 6 Why? Reason 6. (7) Statement 7 Why? Reason 7. (8) Statement 8 Why? Reason 8. QED DRAWING 30