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Each chromosome has one DNA molecule Each chromosome has many genes A gene produces a protein that give rise to a phenotype A gene has many forms- alleles Different alleles are caused by different changes in the same gene Mutations in different genes CAN give you the same phenotype.
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Each chromosome has one DNA molecule Each chromosome has many genes A gene produces a protein that give rise to a phenotype A gene has many forms- alleles Different alleles are caused by different changes in the same gene Mutations in different genes CAN give you the same phenotype Lecture 10: What is a gene? chromosome Forked bristle Many genes yellow Blanco eye Shaven body White eye Genes on DNA b1 w1 w2 b2 w3 Mutations in white Mutations in blanco
Ornithine Citruline Arginine Enzyme1 Enzyme2 Complementation The complementation test is a rapid method of determining whether two independently isolated mutants with the same phenotype (in the same pathway) are in one or two (or more) genes. Glutamic acid- Both mutant1 and mutant2 cannot make arginine. If you did not know the pathway you would wonder if these two mutants were mutations in the same gene or mutations in two different genes If you are working with Neurospora, you can feed the intermediate (Citruline) to the mutants and see if they can now make arginine. You are “complementing” the mutants with intermediates Mutant1+ citruline=cell makes arginine Mutant2+citruline=cell cant make arginine- mutant It is not often this easy. The wildtype eye color in flies is red Say two different laboratories isolated mutants in that had white eyes. You cant feed flies eye color precursor to figure things out!
This process might also identify multiple mutants for the steps in the pathway! B----> E----> A----> N Mut3 Mut1 mut4 Mut2 mut1 and mut4 might be two different mutations in the same gene. OR Mutations in two different genes that work in the same pathway B----> E----> S--- A----> N Mut3 Mut1 mut4 Mut2
White and Blanco-one or two genes? QUESTION Are the two independently isolated mutations THAT HAVE THE SAME WHITE EYE PHENOTYPE disrupting the same or different genes? Precursor (white) Product (red pigment) Enzyme1 Gene1 Blanco=White???? OR Precursor (white) Intermediate (white) Product (red pigment) Enzyme1 Enzyme2 Gene1 White Gene2 Blanco
Easy way!!! There is an easier way QUESTION: IS BLANCO THE SAME GENE AS WHITE or IS BLANCO AND WHITE TWO DIFFERENT GENES The following cross is performed: True breeding Blanco x true breeding white
The actual Cross Cross white (w) x blanco (b) White Blanco Female male w/w x b/b
If White and Blanco are the same gene …. Precursor (white) Product (red pigment) Enzyme1 White= Blanco wwww x wbwb (white eye) (white blanco eye) F1 wwwb Phenotype= ????? In the F1 will the flies be red eyed or white eyed? All white
The cross WHITE EYE What are genotypes and phenotypes of the cross ww x bb b w w b (?) What is the eye-color of the w/b fly? ?White or Red???? ww wb
Precursor -------> product White enzymeA red White x white aa aa F1 aa White What happens if you do a self cross with the F1 a a aa (white) F2
If White and Blanco are two genes…… Precursor (white) Intermediate (blanco) Product (red pigment) Enzyme1 Enzyme2 Gene1 White Gene2 Blanco wwwwBBxWWbb (white eye) (blanco eye) F1 Www Bb phenotype= ????? In the F1 what percentage of flies would be red eyed and what percentage would be white eyed? All red
wwwwBBxWWbb (white eye) (blanco eye) F1 Www Bb phenotype= RED In the F1 what percentage of flies would be red eyed and what percentage would be white eyed? All red ww B bb W
aB Ab ab AB AaBb AB AABB AABb AaBB AAbB AabB Ab aABb aABB aB ab aAbB Gene interactions give 9:7 Precursor----> intermediate----> product white white red EnzA EnzB White x white aaBB AAbb F1 AaBb (phenotype= red) What happens if you do a self cross with the F1 AAbb Aabb F2 aaBb aaBB aabB aAbb aabb 9 A-B- red 3A-bb white 3aaB- white 1aabb white
singed forked yellow Shaven body blanco white singed forked yellow Shaven body Blanco white Map Genes You could map each mutation. If Blanco = white then the two mutations WILL map to the same spot on the chromosome. That would indicate that they are the SAME GENE -two different alleles! If on the other hand the two mutations map to different regions of the chromosome (or different chromosomes) then that would indicate that they are two different genes. Mapping genes takes lots of crosses and is time consuming There is an easier way!
W+ b w W+ b w b B+ How many genes? The answer to the question (What is the eye-color of the w/b fly?) depends on whether the w and b mutations disrupt the same gene or two different genes. What if the w and b mutations disrupt the same gene? w b w b F1 white=blanco If the F1 w/b flies are white-eyed, we know that the white and blanco mutations disrupt one gene. What if w and b mutations disrupt two genes? W+ b w B+ w B+ F1 If the F1 w/b flies are red-eyed, we know that the white and blanco mutations disrupt two genes.
singed forked yellow Shaven body blanco white Single gene If the F1 flies are white-eyed, the mutations disrupt the same gene. A geneticist would say the two mutations do not complement one another because normal function is not restored. If there is a single gene then ****Nomenclature**** If the researchers discover that blanco (b) and white (w) are mutations within the same gene, there is a problem. The same gene has two names. One would like to have names that indicate that these are two alleles of the same gene. These are renamed White becomes w1 Blanco becomes w2 or wb
Two genes If on the other hand the w/b F1 flies are red-eyed, we know that the white and blanco mutations disrupt two genes. Geneticist would say that these two mutations complement one another. They complement because normal function is restored Say in the complementation test you get red eyed females There are two genes --- W and B. If there are two genes then: How do these two genes relate to one another? (one gene one enzyme)
W+ w b B+ white singed forked yellow Shaven body blanco blanco white Two genes If the F1 w/b females are red-eyed, then white and blanco mutations disrupt two genes. You say that these two mutations complement one another. They complement because normal function is restored There are two genes --- W and B. If there are two genes then: How do these two genes relate to one another (one gene one enzyme) Precursor white Product red Intermediate white Enzyme1 Enzyme2 gene1 gene2
Precursor white Product red Intermediate white Enzyme1 Enzyme2 gene1 gene2 OR Precursor white Product red Intermediate white Enzyme1 Enzyme2 gene2 gene1
Molecular basis of mutations Now what is the molecular basis for two mutations within the same gene? Lets say that w1 and w2 both disrupt geneW What is a gene? It’s a piece of DNA with a specific sequence DNA consists of a linear array of the four nucleotides Adenine- Cytosine- Guanine- Thymine ACGT Specific DNA sequence = gene = protein ATGCCCCCCCCCCCCCCCCCCCTAA = GeneW = proteinW The nucleotides in the sequence of the gene is critical for its proper function.
Mutant genes Nucleotide sequence of the normal W gene: ---ATGCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCTAA--- ---TACGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGATT--- The sequence of the w1 mutation of gene W ---ATGCCCCCCCCCCCCCCCCCCCCCCCCCCTCCCTAA--- ---TACGGGGGGGGGGGGGGGGGGGGGGGGGGAGGGATT--- The sequence of the w2 mutation of gene W ---ATGCCCCACCCCCCCCCCCCCCCCCCCCCCCCCTAA--- ---TACGGGGTGGGGGGGGGGGGGGGGGGGGGGGGGATT--- So at the molecular level, the w1/w2 white female fly would be depicted as: ---ATGCCCCCCCCCCCCCCCCCCCCCCCCCCTCCCTAA--- ---TACGGGGGGGGGGGGGGGGGGGGGGGGGGAGGGATT--- ---ATGCCCCACCCCCCCCCCCCCCCCCCCCCCCCCTAA--- ---TACGGGGTGGGGGGGGGGGGGGGGGGGGGGGGGATT---
Precursor white Product red Intermediate white Enzyme1 Enzyme2 Gene B Bw3 Gene A Aw1 Aw2 Two White Genes Lets make things more complicated. w1 and w2 disrupt one gene (geneA). w3 disrupt a second gene (geneB) Disruptions in geneA (Aw1 and Aw2) and geneB (Bw3) give rise to white eyes. HOW DO YOU FIGURE OUT THAT w1 and w2 disrupt gene A and w3 disrupts geneB
Precursor white Product red Intermediate white Enzyme1 Enzyme2 Gene B Gene A Genes Disruptions in geneA and geneB both give rise to white eyes. Cross a Aw1 fly with a Aw2 fly and see if you get red eyes. If w1 and w2 disrupt geneA, they will/will not complement . What about Bw3?
white blanco Precursor white Product red Intermediate white White enzyme Blanco enzyme w1/w1 B/B w2/w2 B/B w1/w2 B/B F1=
white blanco Precursor white Product red Intermediate white White enzyme Blanco enzyme w1/w1 B/B W/W b(w3)/b(w3) W/w1 b(w3)/B F1=
Complementation analysis Genotype eye color complementation Aw1/Aw2 white N Aw1/Bw3 red Y Aw2/Bw3 red Y w1, w2 = geneA= complementation groupA (multiple alleles) w3,= geneB= complementation groupB
Suppose we isolate 5 delta wing mutations d1 d2 d3 d4 d5 We want to know how many genes are disrupted in these mutations and which mutations are in the same complementation group
Complementation crosses We systematically perform crosses First we perform the cross d1/d1 x d2/d2 F1 d1/d2 are produced wing= flat or delta If they are flat, they disrupt -------- gene Then we perform d1/d1 x d3/d3 F1 d1/d3 wing=flat or delta You construct a complementation table + flat wing - is delta wing Mutation complement mutation don’t complement Different genes same gene
Complementation crosses You construct a complementation table + is flat wing - is delta wing Mutation complement mutation don’t complement Different genes same gene d1 d2 d3 d4 d5 d1 - - + + - d2 - - + + - d3 ++ - - + d4 + + - - + d5 - - + + - Gene1= alleles (d1, d2, d5) Gene2= alleles (d3, d4)
The pathway Precursor delta Product flat Intermediate delta Enzyme1 Enzyme2 Gene2 (allele d3, d4) Gene1 (allele d1, d2, d5)