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Equations with variables on both sides notes Absent Copy Thurs/Fri 2/21,22.
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Equations with variables on both sidesnotesAbsent CopyThurs/Fri 2/21,22
1. Use G E M A (to simplify) on each side of the = sign. 2. Find the side of the = sign that has the smallest coefficient (#) w/the variable and do the inverse opp. and move it to the other side of the = sign. Ex: 3x + 4 = 6 + 5x-3x-3x 02x 3. Move the terms(inverse opp.) to one side of the = sign. 4. Use inverse opp. of mult./div. to get variableby itself to solve equation.
Example 1 • Solve and check: 5a – 5 = 7 + 2a -2a-2a 3a 0 3a – 5 = 7 +5+5 0 12 3a=12 3 3 a = 4 Solution • Is there any GEMA(simplifying) that needs to be done in this equation. YES or NO • What is the smallest coefficient with the a. • The 2 is the smallest number with the a • What inverse opp. do we use to move the 2a. • We use the inverse opp. Of addition and subtract 2a from both sides. • What term do we move using the inverse opp. -5 or 7 • Now what inverse opp. Do we use to solve for a. • We use the inverse opp. Of mult. and divide by 3 on each side. a = 4
Example 2 • Solve and check 4(x – 5) + 2 = x + 3 4x – 20 + 2 = x + 3 4x – 18 = x + 3 -1x-x 3x 0 3x – 18 = 3 +18 = +18 0 21 3x = 21 33 x = 7 Solution • What do we do with the 4 on the outside of the groupings? • We have to use the distributive property. • Do we have to use any GEMA to simplify? YES or NO • What is the smallest coefficient with the x. • The 1 is the smallest number with the x. • What inverse opp. do we use to move the 1x. • We have to use the inverse opp. of addition and subtract 1x from both sides. • What term do we move using the inverse opp. -18 or 3 • Now what inverse opp. Do we use to solve for x. • We have to use the inverse opp. Of mult. And divide by 3 on both sides. X = 7