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2-D Motion

2-D Motion. Vectors. Review of Trig. Find y, H, θ2, when X=4.7 m and θ1=33 ° SOH, CAH, TOA Sinθ =O/H Cosθ =A/H Tanθ =O/A. Review of Trig. Find y, H, θ2, when X=4.7 m and θ1=33 ° SOH, CAH, TOA Opposite and Adjacent refer to being opposite and adjacent of the angle you referring to!

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2-D Motion

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  1. 2-D Motion Vectors

  2. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • Sinθ=O/H • Cosθ=A/H • Tanθ=O/A

  3. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • Opposite and Adjacent refer to being opposite and adjacent of the angle you referring to! • Hypotenuse is always opposite of the right angle

  4. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • Using θ1=33 and x=4.7 • We can use CAH

  5. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • Adjacent=4.7 m, Hypotenuse=?, θ1=33 • Cosθ=A/H • Cos33=4.7/H • H=5.6 m

  6. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • H=5.6 m • Now we can use the Pythagorean theorem • A2 +B2 = C2

  7. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • H=5.6 m, X=4.7 m y=? • H is always C • 4.72 + Y2 = 5.62 • 22.09 + Y2 =31.4 • Y=3.0 m

  8. Review of Trig • Find y, H, θ2, when X=4.7 m and θ1=33° • SOH, CAH, TOA • Find θ2 • The angles of a right triangle = 180 • 33+ 90+ x = 180 • X=57° • Or how else can we solve this problem?

  9. Clicker Question ? • Hypotenuse=500 m • Theta=20 degrees • A-20 • B-170 • C-180 • D-250 • E-470

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