1 / 11

Test Review! Study last weeks open notebook quiz, you have the answer key!!

Test Review! Study last weeks open notebook quiz, you have the answer key!!. HW: PROJECTS! PROJECTS ! Submit a rough draft and I will check it. No more excepted after Monday Do Now: Think of one question that Ms. McGrath will put on the test!. #1. Perimeter: 8 + 10 + 10 + ½ Circumference

chogan
Download Presentation

Test Review! Study last weeks open notebook quiz, you have the answer key!!

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Test Review! Study last weeks open notebook quiz, you have the answer key!! HW: PROJECTS! PROJECTS! Submit a rough draft and I will check it. No more excepted after Monday Do Now: Think of one question that Ms. McGrath will put on the test!

  2. #1 • Perimeter: • 8 + 10 + 10 + ½ Circumference • ½ C = πd / 2 • π (8) / 2 = 4 π • Total: 28 + 4 π feet • Area: • Rectangle = L x W ½ circle = π r^2 / 2 • (8)(10) + π (4)^2 / 2 • 80 + 8 π square feet

  3. #2 • Area of square – area of circle • Square: L x W = 8 * 8 = 64 sq inches • Area of circle = π r ^2 = π (4) ^2 = 16π • Area of circle= 16 π • Total area = 64 - 16 π square inches

  4. #3 Large D = 20 ft Small D = 10 ft • Area of large circle – area of small circle • Large = π r ^2 • R = ½ d r = 10 • A = π (10)^2 = 100π • Area of small circle = π r ^2 • R = ½ d r = 5 • A = π r^2 = π(5)^2 = 25 π • Total area = 100π – 25 π = 75 π

  5. # 4 • Volume of a rectangular pyramid • V = (area of base * height) ÷ 3 • V = (4 x 6) (10) / 3 • = 240/3 = • V = 80 cubic cm

  6. #5 • Area of triangle with base of 20 and height of 5 inches • A tri = ½ b h • A = ½ (20) (5) • A = 50 square inches

  7. # 6 • Volume of a cylinder D = 30 cm ; H = 10 cm • V = π r^2 H • V = π (15)^2 (10) • V = 2250π cubic cm

  8. #7 • Volume of rectangular prism with length of 4 units, width 5 units and height of 6 units • V = lwh • V = (4)(5)(6) = 120 cubic units • Surface area: SA = 2 lw + 2 lh + 2 wh • = 2 (4) (5) + 2(4)(6) + 2 (5)(6) • = 40 + 48 + 60 = 148 square units • What if top is off? • Only one Length*width

  9. SA = lw + 2 lh + 2 wh • (4) (5) + 2(4)(6) + 2 (5)(6) • = 20 + 48 + 60 = 128 square units

  10. #8 • Area of pyramid • (Base area * height) ÷ 3 • [(4 x 7) (10)] / 3 • 280 / 3 = 93 1/3 cubic cm

  11. # 9 • Area of square – area of circle • Square = (14)(14) = 196 • A rea of circle = π r ^2 • Area = π (7) ^2 • Area = 49 π • Total area = 196 - 49 π square cm

More Related