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1 st 6 Weeks Review. Test Wednesday Remember your pencil and calculator. Part I. Classify each of the following substances as; an element, a compound, a solution, or a heterogeneous mixture.
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1st 6 Weeks Review Test Wednesday Remember your pencil and calculator
Part I. Classify each of the following substances as; an element, a compound, a solution, or a heterogeneous mixture.
Part II. In the spaces provided, describe the distinguishing characteristics of the major categories of matter. • Element – A substance that cannot be separated or broken down into simpler substances by chemical means; can be found on periodic table. • Compound – A substance made up of atoms of two or more different elements joined by chemical bonds • Solution – a homogenous mixture throughout which two or more substances are uniform. • Mixture – a combination of two or more substances that are not chemically combined.
Part III. Classification - State whether each of the following changes would be physical or chemical.
Part IV. Define - Use your own words to define each of the following terms in the space provided. • Chemical Change – a change that occurs when one or more substances change into entirely new substances with different properties. • Physical Change – A change of matter from one form to another without a change in chemical properties. • Change of State of Phase – When a substance changes from one state of matter to another.
Part V • 18 m = 1800 cm • 167 mm = (typo change to m) 0.167 m • 500 kg = 500,000 g • 23 dm = 0.023 hm • 1,589 dl = (typo change to kl) 0.1589 kl • 700 ml = 0.000700 kl • 5 cm = 50 mm • 35.45 mg = 0.0003545 hg • 0.5 l = 0.0005 kl • 130 Dg = 13.0 kg
Density (#11) • m = 453 g; V = 225 cm3 d = m/v = 453 g/225 cm3 = 2.01 g/ cm3 b) m = 5.0 g; V = 10.0 cm3 d = m/v = 5.0g/10.0 cm3 = 0.50 g/ cm3 c) m = 26.1 g; V = 2.0 mL d = m/v = 26.1g/2.0 mL = 13.1 g/mL #12 m = 75.2 g; V = 89.2 mL d = m/v = 75.2 g / 89.2 mL = .84 g/mL
#13 m = 1450 g; V = 542 mL d = m/v = 1450 g / 542 mL = 2.68 g/mL #14 Scientific Method • Problem • Hypothesis • Experiment • Analyze Data • Conclusion/Retest
Gas Laws Boyles Law P1V1 = P2V2 (inverse relationship) When pressure increases volume decreases When pressure decreases volume increases Charles Law V1/T1 = V2/T2 (direct relationship) When temperature increases volume increases When temperature decreases volume decreases