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Pressure, Drag and Lift for Uniform Flow Over a Cylinder. a 2 = 1. Pressure, Drag and Lift for Uniform Flow Over a Cylinder. Along the cylinder, r = a , the velocity components become:. u θ is maximum at θ = π /2 and 3 π /2; zero at θ = 0 and θ = π.
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Pressure, Drag and Lift for Uniform Flow Over a Cylinder a2 = 1
Pressure, Drag and Lift for Uniform Flow Over a Cylinder Along the cylinder, r = a, the velocity components become: uθ is maximum at θ = π/2 and 3 π /2; zero at θ = 0 and θ = π
The pressure distribution can be obtained using Bernoulli’s equation: dimensionless pressure coefficient Cp
The drag on the cylinder may be calculated through integration of the pressure over the cylinder surface: Fy Fx The drag on the cylinder acts parallel to the flow. The lift is perpendicular to the flow:
Pressure, Drag and Lift for Uniform Flow Over a Rotating Cylinder Along the cylinder, r = a, the velocity components become:
The pressure distribution can be obtained using Bernoulli’s equation: dimensionless pressure coefficient Cp
The drag and lift can be obtained by integrating the pressure over the cylinder surface pc : Still no drag for a rotating cylinder There is lift proportional to density, upstream velocity, and strength of vortex -- Kutta – Jukowski law Lifting effect for rotating bodies in a free stream is called Magnus effect
Example of Pressure, Drag and Lift for Uniform Flow Over a Cylinder 3 m The drag on the cylinder may be calculated through integration of the pressure over half the cylinder surface, from 0 to π. u = 20 m/s That’ll be with the outside pressure, inside pressure p0 should also be considered:
3 m u = 20 m/s
The lift on the object may be calculated through integration of the pressure over half the cylinder surface, from 0 to π. 3 m u = 20 m/s
3 m u = 20 m/s
Lift for half-cylinder, 3 m high, influenced by wind (air density) Gale Force tropical depres-sion tropical storm hurricane
Lift for half-cylinder, 1 m high, influenced by flow (water density)