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ϕ -bending in an infinite solenoid

ϕ -bending in an infinite solenoid. ρ = p T /.3 B α = R c / ρ Δϕ 1 = α /2 Δ ϕ = Δϕ 1 R c /R d Δ ϕ = (.3 B/ p T ) . R c 2 /R d /2 p T =20 GeV /c B=2T R c =1m D1 : Rd>1.3 m, Δ ϕ < 11mrad D2 : Rd>2.2 m, Δ ϕ < 7 mrad D3 : Rd>3.4 m, Δ ϕ < 4 mrad. Δϕ.

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ϕ -bending in an infinite solenoid

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  1. ϕ-bending in an infinite solenoid • ρ = pT /.3 B • α = Rc/ρ • Δϕ1 = α/2 • Δϕ = Δϕ1Rc/Rd • Δϕ= (.3 B/ pT) . Rc2/Rd/2 • pT=20 GeV/c • B=2T • Rc=1m • D1 : Rd>1.3 m, Δϕ< 11mrad • D2 : Rd>2.2 m, Δϕ< 7 mrad • D3 : Rd>3.4 m, Δϕ< 4 mrad Δϕ Detector (Rd) Δϕ1 α ρ Solenoid (Rc)

  2. Field model of the real solenoid B=2T z2=4m z1=2m

  3. Computing ∫BzdR 1 2 Rc • Case 1: ∫BzdR = B Rc • Case 2: ∫BzdR= B (Rt + (Rc-Rt)(2*Z2-Z1-Ze)/(Z2-Z1)/2) • Case 3: ∫BzdR=B (Rt+Re)/2 3 Re Rt Rt Ze Z1 Z2

  4. ∫BzdR as a function of η

  5. ϕ-bending as a function of η

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