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X Chemistry Unit 8 The Mole. Problem Solving involving Chemical Compounds. Vocab:. Percent composition – mass of the part divided by mass of the whole times 100 Empirical Formula – the simplest whole number ratio of atoms in a compound
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X Chemistry Unit 8The Mole Problem Solving involving Chemical Compounds
Vocab: • Percent composition – mass of the part divided by mass of the whole times 100 • Empirical Formula – the simplest whole number ratio of atoms in a compound • Molecular Formula- the true whole number ratio of atoms in a compound
Vocab: • Molar Mass- the mass of 1 mole of a substance • Equal to the atomic mass for elements • For a compound, the sum of the atomic masses for all the atoms in a compound • Units = grams/mole = g/mol • Mole - the amount of substance that is equal to 6.02x1023 particles of that substance
Vocab: • Representative particle- the smallest particle of a substance; defined by the type of substance: • Element = atom • Covalent compound = molecule • Ionic compound = formula unit • Charged atom = ion
Vocab: • Avogadro’s Number- the number of particles in 1 mole of any substance • Avogadro’s # = 6.02x1023 • Molar Volume- the volume of 1 mole of ANY gas at STP (Standard Temperature and Pressure = 0°C and 1atm), • 22.4 Liters
What is a Mole? • Amedeo Avogadro (Italian Mathematician) • used Carbon as the basis for the masses of the other elements • devised a counting relationship between grams and moles • 1 mole = 6.02x1023 atoms of any element • 1 mole of carbon = 12.0 g Carbon • (matches the atomic mass on the P.T.)
What is a Mole? (REAL WORLD EXAMPLE) Relationships: • 1 dozen = 12 donuts just like 1 mole = 6.02x1023 atoms BUT: • 1 dozen feathers = 0.015 grams and • 1 dozen bricks = 32,400 grams!
What is a Mole? • The mass of 1 mole of any element will be different than 1 mole of any other element • Practice: • What are the masses of 1 mole of the following elements? • Magnesium = • 24.31 g/mol • Nitrogen = • 14.01 g/mol
Determining Molar Mass: • Steps in Solving: • Write the element symbols in the formula down the left hand side of the paper • Multiply the number of atoms by the molar mass of that element according to the P.T. and rounded to the tenths place • Sum the products from step 2 • the units on your final answer are g/mol (grams per mole)
Determining Molar Mass: • Examples: • CO2 • (NH4)2SO4
Mole Conversions Moles! Use Avogadro’s # (6.02 x 1023) Use molar mass Mole Conversions Representative particles (atoms, molecules, formula units, ions) Mass
Converting between Moles and Grams: • Mole-Mass Conversions • Dimensional Analysis!! Use molar mass as conversion factor! • Moles to grams: • # of moles molar mass (g) = # of grams 1 mole • Grams to moles: • # of grams 1 mole = # of moles Molar mass (g)
Converting between Moles and Grams: Examples: • How many moles of CCl4 are their in 523.4g?
Converting between Moles and Grams: Examples: (cont.) • How many grams of Na are there in 12.3 moles of Na?
Conversions Between Moles & Particles: Use Avogadro’s Number!! Examples: How many atoms of carbon are contained in 0.230 moles of C?
Conversions Between Moles & Particles Examples: How many molecules of sodium chloride are contained in 0.145 moles of NaCl?
Conversions Between Moles & Particles Challenge!! How many molecules of barium chloride are contained in 1.07 grams of barium chloride?
Percent Composition Problems: • 2 types: • Using data measured in grams to find percentage of element in some given sample (More specific) • Using a chemical formula to find percentage of each element in a compound (More general)
Percent Composition Problems: • Type 1: (just like the separation lab!) • % of element in a specific sample
Percent Composition Problems: Examples: If 20.55 g of sodium combines completely with 31.75 g of chlorine to form a compound, what is the % composition of each element in this compound?
Percent Composition Problems: • Type 2: • Mass of element in 1 mole of a compound
Percent Composition Problems: Example: What is the percent composition of each element in C12H22O11?
Empirical Formula Calculations Percent to mass Mass to moles Divide by Small Multiply ‘til whole Divide by smallest mole value % g moles empirical formula
Multiply ‘til Whole Hints Common Possible Endings: .33 x 3 .25 x 4 .67 x 3 .50 x 2
Determining the Empirical Formula of a Compound: Steps for Solving: • Convert grams of each element to moles using molar mass • Inspect your answers and find the smallest number of moles of all the answers • Divide each number of moles for each element by the smallest determined in step 2 • Your answers to step 3 have no units since it was moles/moles they cancel out!! • IF the ratios do not come out to a whole number, multiply all values by some whole number to get all whole numbers • These numbers are the subscripts for each of the elements in the empirical formula
Determining the Empirical Formula of a Compound: Example: Find the empirical formula for a compound composed of 78% iron and 22% oxygen.
Determining the Empirical Formula of a Compound: A compound is 81.1 % boron and 18.9% hydrogen. What is the empirical formula of this compound?
Determining the Molecular Formula of a Compound: • Steps for Solving: • Find the Empirical Formula • Find the molar mass of the Empirical Formula • Divide the Molecular molar mass by the Empirical molar mass • The answer to step 3 is the factor you multiply each subscript in the Empirical Formula by to get the Molecular Formula
Determining the Molecular Formula of a Compound: A compound of B and H is 81.10% B and 18.9% H. Its empirical formula is B2H5. What is its molecular formula if the molar mass of the compound is 53.3 g/mol?