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Unit 5: The Mole

Unit 5: The Mole. Molar Mass. The sum of the atomic masses of all the atoms in the formula of a compound or molecule. Calculating Molar Mass. Calculate the molar mass for H 2 O: H = 2 x 1.0079 g = 2.0158 g O = 1 x 15.999 g = 15.999 g Molar mass of water = 18.0148 g

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Unit 5: The Mole

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  1. Unit 5: The Mole

  2. Molar Mass • The sum of the atomic masses of all the atoms in the formula of a compound or molecule

  3. Calculating Molar Mass • Calculate the molar mass for H2O: • H = 2 x 1.0079 g = 2.0158 g • O = 1 x 15.999 g = 15.999 g Molar mass of water = 18.0148 g • Calculate the molar mass for Fe2(SO4)3: • Fe = 2 x 58.847 g = 117.694 g • S = 3 x 32.06 g = 96.18 g • O = 12 x 15.999 g = 191.988 g Molar mass of iron (III) sulfate = 405.862 g

  4. Practice Practice Practice!!!

  5. The Mole • A counting word, just like a dozen • A dozen = 12 • A mole = 6.02 x 1023 • Two moles of marbles = 2 x 6.02 x 1023 • Three moles of hair pins = 3 x 6.02 x 1023 • 6.02 x1023 also known as Avogadro’s # • Amedeo Avogadro (Italian Scientist) aided in this development

  6. Mole Conversion Factor Molar mass (g) of substance = 6.02 x 1023 molecules of substance = 1 mole of substance

  7. Mole Conversion Factor Possibilities • 1 mole molar mass (g) • molar mass (g) 1 mole • 1 mole 6.02 x 1023 atoms or molecules • 6.02 x 1023 atoms or molecules 1 mole

  8. Mole Conversion Factor Possibilities • molar mass (g) 6.02 x 1023 atoms or molecules • 6.02 x 1023 atoms or molecules molar mass (g) • Use the word atoms when describing a single element; use the word molecule when describing molecules and compounds

  9. Mole Conversion Examples Molar mass = Avogadro’s # = 1 mole 18.0148 g of H2O = 6.02 x 1023 molecules of H2O = 1 mole of H2O 405.862 g of Fe2(SO4)3 = 6.02 x 1023 of Fe2(SO4)3 = 1 mole of Fe2(SO4)3 6.941 g of Li = 6.023 x 1023 atoms of Li = 1 mole of Li

  10. Mole Conversion Practice Problem 1 • If 5,000,000 chlorine atoms are used to disinfect water, how many moles is that? 5,000,000 atoms Cl x 1 mole Cl = 8.3 x 1023 mole Cl 6.02 x 1023 atoms Cl 8.3 x 1023 mole Cl  8 x 1023 mole Cl Correct Sig Fig

  11. Mole Conversion Practice Problem 2 • Thirty moles of carbon monoxide could be a lethal amount. How many grams is that? 30 moles CO x 28.01 g of CO = 840.3 g of CO 1 mole CO 840.3 g CO  800 g CO Correct Sig Fig

  12. Mole Conversion Practice Problem 3 • One liter of water weighs 1,000 g. How many water molecules is that? 1,000 g H2O x 1 mole H2O x 6.02 x 1023 molecules H2O = 3.3 x 1023 molecules H2O 18.0148 g H2O 1 mole H2O 3.3 x 1023molecules H2O  3 x 1023 molecules H2O Correct Sig Fig

  13. Practice Practice Practice!!!

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