1 / 10

Section 10.5

Chapter 10. Section 10.5. Exercise #19. 25 + 2x. 25 ft. 15 + 2x. 15 ft. x. x. A = 650 ft 2.

conan-dyer
Download Presentation

Section 10.5

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 10 Section 10.5 Exercise #19

  2. 25 + 2x 25 ft 15 + 2x 15 ft x x A = 650 ft2 Construction. A rectangular garden is to be surrounded by a walkway of constant width. The garden’s dimensions are 15 ft by 25 ft. The total area, garden plus walkway, is to be 650 ft2. What must be the width of the walkway?

  3. 25 + 2x 25 ft 15 + 2x x 15 ft x A = 650 ft2 (25 + 2x) (15 + 2x) = 650 375 + 50x + 30x + 4x2 = 650 4x2 + 80x – 275 = 0

  4. 25 + 2x 25 ft 15 + 2x x 15 ft x A = 650 ft2 a = 4 b = 80 c = –275

  5. 25 + 2x 25 ft 15 + 2x x 15 ft x A = 650 ft2

  6. 25 + 2x 25 ft 15 + 2x x 15 ft x A = 650 ft2

  7. Chapter 10 Section 10.5 Exercise #43

  8. Business and finance. Suppose that the profit P, in dollars, of producing and selling xappliances is given by P = –3x2+ 240x – 1800. How many appliances must be produced and sold to achieve a profit of $2325?

  9. P = –3x2+ 240x – 1800 2325 = –3x2+ 240x – 1800 0 = –3x2+ 240x – 4125 0 = x2– 80x + 1375 0 = (x – 25)(x – 55) x = 25 or 55 25 or 55 appliances

More Related