240 likes | 479 Views
SERIES COMBINATIONS. PARALLEL COMBINATION. SERIES PARALLEL RESISTOR COMBINATIONS. UP TO NOW WE HAVE STUDIED CIRCUITS THAT CAN BE ANALYZED WITH ONE APPLICATION OF KVL(SINGLE LOOP) OR KCL(SINGLE NODE-PAIR). WE HAVE ALSO SEEN THAT IN SOME SITUATIONS IT IS ADVANTAGEOUS TO COMBINE RESISTORS
E N D
SERIES COMBINATIONS PARALLEL COMBINATION SERIES PARALLEL RESISTOR COMBINATIONS UP TO NOW WE HAVE STUDIED CIRCUITS THAT CAN BE ANALYZED WITH ONE APPLICATION OF KVL(SINGLE LOOP) OR KCL(SINGLE NODE-PAIR) WE HAVE ALSO SEEN THAT IN SOME SITUATIONS IT IS ADVANTAGEOUS TO COMBINE RESISTORS TO SIMPLIFY THE ANALYSIS OF A CIRCUIT NOW WE EXAMINE SOME MORE COMPLEX CIRCUITS WHERE WE CAN SIMPLIFY THE ANALYSIS USING THE TECHNIQUE OF COMBINING RESISTORS… … PLUS THE USE OF OHM’S LAW
FIRST WE PRACTICE COMBINING RESISTORS SERIES 6k||3k (10K,2K)SERIES
EXAMPLES COMBINATION SERIES-PARALLEL If the drawing gets confusing… Redraw the reduced circuit and start again RESISTORS ARE IN SERIES IF THEY CARRY EXACTLY THE SAME CURRENT RESISTORS ARE IN PARALLEL IF THEY ARE CONNECTED EXACTLY BETWEEN THE SAME TWO NODES
AN “INVERSE SERIES PARALLEL COMBINATION” Given the final value Find a proper combination SIMPLE CASE NOT SO SIMPLE CASE
EFFECT OF RESISTOR TOLERANCE RANGES FOR CURRENT AND POWER? THE RANGES FOR CURRENT AND POWER ARE DETERMINED BY THE TOLERANCE BUT THE PERCENTAGE OF CHANGE MAY BE DIFFERENT FROM THE PERCENTAGE OF TOLERANCE. THE RANGES MAY NOT EVEN BE SYMMETRIC
CIRCUIT WITH SERIES-PARALLEL RESISTOR COMBINATIONS THE COMBINATION OF COMPONENTS CAN REDUCE THE COMPLEXITY OF A CIRCUIT AND RENDER IT SUITABLE FOR ANALYSIS USING THE BASIC TOOLS DEVELOPED SO FAR. COMBINING RESISTORS IN SERIES ELIMINATES ONE NODE FROM THE CIRCUIT. COMBINING RESISTORS IN PARALLEL ELIMINATES ONE LOOP FROM THE CIRCUIT • GENERAL STRATEGY: • REDUCE COMPLEXITY UNTIL THE CIRCUIT • BECOMES SIMPLE ENOUGH TO ANALYZE. • USE DATA FROM SIMPLIFIED CIRCUIT TO • COMPUTE DESIRED VARIABLES IN ORIGINAL • CIRCUIT - HENCE ONE MUST KEEP TRACK • OF ANY RELATIONSHIP BETWEEN VARIABLES
…OTHER OPTIONS... FIRST REDUCE IT TO A SINGLE LOOP CIRCUIT SECOND: “BACKTRACK” USING KVL, KCL OHM’S
AN EXAMPLE OF “BACKTRACKING” A STRATEGY. ALWAYS ASK: “WHAT ELSE CAN I COMPUTE?”
SERIES PARALLEL THIS IS AN INVERSE PROBLEM WHAT CAN BE COMPUTED?
THEN THE CIRCUIT WOULD BECOME LIKE THIS AND BE AMENABLE TO SERIES PARALLEL TRANSFORMATIONS IF INSTEAD OF THIS WE COULD HAVE THIS THIS CIRCUIT HAS NO RESISTOR IN SERIES OR PARALLEL Ra+(Rc+R4)||(Rb+R5)
REPLACE IN THE THIRD AND SOLVE FOR R1 SUBTRACT THE FIRST TWO THEN ADD TO THE THIRD TO GET Ra
DELTA CONNECTION LEARNING EXAMPLE: APPLICATION OF WYE-DELTA TRANSFORMATION ONE COULD ALSO USE A WYE - DELTA TRANSFORMATION ...
CONVERT THIS Y INTO A DELTA? SHOULD KEEP THESE TWO NODES! IF WE CONVERT TO Y INTO A DELTA THERE ARE SERIES PARALLEL REDUCTIONS! LEARNING EXAMPLE THE RESULTING CIRCUIT IS A CURRENT DIVIDER
NOTICE THAT BY KEEPING THE FRACTION WE PRESERVE FULL NUMERICAL ACCURACY WYE DELTA CIRCUIT AFTER PARALLEL RESISTOR REDUCTION
SMALLER RESISTANCE FOR HIGHER POWER MEDIUM OR LOW HIGH
This is the set up in the car Circuit Representation WHEN THE STARTER IS ENGAGED THE VOLTAGE DROP ACROSS THE RESISTENCE INCREASES 100 FOLD --- LIGHTS DIM!
APPPLICATIONS Balance condition For bridge circuit Measure R3 with scale empty Measure R3 when truck is on sclae Weight is determined in the following manner. The change in R3 required to balance the bridge represents the change in strain, which when multiplied by the modulus of elasticity yields the change in stress. The change in stress multiplied by the cross-sectional area of the cylinder produces the change in load, which determines the weight
Highest V2: No lamp connected Lowest V2: All lamps ON (5 lamps in parallel with R2) Equivalent circuit
More realistic model – I_signal is NOT I_sensor. There is a current division determined by Rs and R_wire (length of wire becomes important) DESIGNS Design a current-to-voltage converter that will output 5 V when the current signal Is 20mA Assume that the controller does not use any current from the I to V converter. In this case a simple resistor behaves as current to voltage converter! Wire resistance does not matter! (within reasonable limits)