1 / 76

Chp-6:Lecture Goals

Chp-6:Lecture Goals. Serviceability Deflection calculation Deflection example . Structural Design Profession is concerned with: Limit States Philosophy: Strength Limit State (safety-fracture, fatigue, overturning buckling e tc.-) Serviceability

corbett
Download Presentation

Chp-6:Lecture Goals

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chp-6:Lecture Goals • Serviceability • Deflection calculation • Deflection example

  2. Structural Design Profession is concerned with: Limit States Philosophy: Strength Limit State (safety-fracture, fatigue, overturning buckling etc.-) Serviceability Performance of structures under normal service load and are concerned the uses and/or occupancy of structures

  3. ;

  4. λ :Amplification factor :Time dependent Factor ζ

  5. Solution:

  6. See Example 2.2 Ma: Max. Service Load Moment

  7. Reinforced Concrete Sections - Example Given a doubly reinforced beam with h = 24 in, b = 12 in., d’ = 2.5 in. and d = 21.5 in. with 2# 7 bars in compression steel and 4 # 7 bars in tension steel. The material properties are fc = 4 ksi and fy= 60 ksi. Determine Igt, Icr , Mcr(+), Mcr(-), and compare to the NA of the beam.

  8. Reinforced Concrete Sections - Example The components of the beam

  9. Reinforced Concrete Sections - Example The compute the n value and the centroid, I uncracked

  10. Reinforced Concrete Sections - Example The compute the centroid and I uncracked

  11. Reinforced Concrete Sections - Example The compute the centroid and I for a cracked doubly reinforced beam.

  12. Reinforced Concrete Sections - Example The compute the centroid for a cracked doubly reinforced beam.

  13. Reinforced Concrete Sections - Example The compute the moment of inertia for a cracked doubly reinforced beam.

  14. Reinforced Concrete Sections - Example The critical ratio of moment of inertia

  15. Reinforced Concrete Sections - Example Find the components of the beam

  16. Reinforced Concrete Sections - Example Find the components of the beam The neutral axis

  17. Reinforced Concrete Sections - Example The strain of the steel Note: At service loads, beams are assumed to act elastically.

  18. Reinforced Concrete Sections - Example Using a linearly varying e and s = Ee along the NA is the centroid of the area for an elastic center The maximum tension stress in tension is

  19. Reinforced Concrete Sections - Example The uncracked moments for the beam

  20. Calculate the Deflections (1) Instantaneous (immediate) deflections (2) Sustained load deflection Instantaneous Deflections due to dead loads( unfactored) , live, etc.

  21. Calculate the Deflections Instantaneous Deflections Equations for calculating Dinst for common cases

  22. Calculate the Deflections Instantaneous Deflections Equations for calculating Dinst for common cases

  23. Calculate the Deflections Instantaneous Deflections Equations for calculating Dinst for common cases

  24. Calculate the Deflections Instantaneous Deflections Equations for calculating Dinst for common cases

  25. Sustained Load Deflections Creep causes an increase in concrete strain Curvature increases Increase in compressive strains cause increase in stress in compression reinforcement (reduces creep strain in concrete) Compression steel present Helps limit this effect.

  26. Sustained Load Deflections Sustain load deflection = l Di Instantaneous deflection ACI 9.5.2.5 at midspan for simple and continuous beams at support for cantilever beams

  27. 5 years or more 12 months 6 months 3 months Sustained Load Deflections x = time dependent factor for sustained load Also see Figure 9.5.2.5 from ACI code

  28. Sustained Load Deflections For dead and live loads DL and LL may have different x factors for LT ( long term ) D calculations

  29. Some percentage of DL (if given) Full DL and LL Sustained Load Deflections The appropriate value of Ic must be used to calculate D at each load stage.

  30. Serviceability Load Deflections - Example Show in the attached figure is a typical interior span of a floor beam spanning between the girders at locations A and C. Partition walls, which may be damaged by large deflections, are to be erected at this level. The interior beam shown in the attached figure will support one of these partition walls. The weight of the wall is included in the uniform dead load provided in the figure. Assume that 15 % of the distributed dead load is due to a superimposed dead load, which is applied to the beam after the partition wall is in place. Also assume that 40 % of the live load will be sustained for at least 6 months.

  31. Serviceability Load Deflections - Example fc = 5 ksi fy = 60 ksi

  32. Serviceability Load Deflections - Example Part I Determine whether the floor beam meets the ACI Code maximum permissible deflection criteria. (Note: it will be assumed that it is acceptable to consider the effective moments of inertia at location A and B when computing the average effective moment of inertia for the span in this example.) Part II Check the ACI Code crack width provisions at midspan of the beam.

  33. Serviceability Load Deflections - Example Deflection before glass partition is installed (85 % of DL)

  34. Serviceability Load Deflections - Example • Compute the centroid and gross moment of inertia, Ig.

  35. Serviceability Load Deflections - Example The moment of inertia

  36. Serviceability Load Deflections - Example The moment capacity

  37. Serviceability Load Deflections - Example Determine bending moments due to initial load (0.85 DL) The ACI moment coefficients will be used to calculate the bending moments Since the loading is not patterned in this case, This is slightly conservative

More Related