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Disproved By: Sierra Baney 2012. Curving A Bullet. Wanted (6/11) Movie CLIP - Wesley's First Curved Bullet (2008) HD - YouTube. Mr. X. Video Breakdown. Mr. X runs out a hallway window from a skyscraper and shoots at a man on a building across the street.
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Disproved By: Sierra Baney 2012
Curving A Bullet • Wanted (6/11) Movie CLIP - Wesley's First Curved Bullet (2008) HD - YouTube
Video Breakdown • Mr. X runs out a hallway window from a skyscraper and shoots at a man on a building across the street. • While in the air he shoots 3 shots. • He lands about 12 feet below his original height.
Involved Physics • Linear Motion: Velocity • Relative Motion • Conservation of Momentum: • Inelastic Collisions • Projectile Motion
Wanted (1/11) Movie CLIP - Cross Kills Mr. X (2008) HD - YouTube
Citadel Building • 131 Dearborn St, Chicago • Total Height: • 580 ft = 177 m • 37 stories
Carbon and Carbide Building • 230 Michigan Avenue, Chicago • Total Height: • 503 ft = 153m • 37 stories
Estimations • Secondary Roof • 400 ft = 121.92m • Height Mr. X drops • 12 ft = 3.66 m
Calculating Velocity • OSHA Minimum Requirement (Office) • 61ft = 18.59m • 3 doorways 18.59 X 3 = 55.78m • OSHA Minimum Requirement (Elevator) 1.74m • 55.78 + 1.74 • Total distance 131.89m in 28 sec
Calculating Velocity (Cont) • Velocity = Distance / Time • 57.53 / 6.3 = 9.13 m/s • 20.42 mph • Fastest recorded speed was 10.35 m/s • top physical condition
David O’Hara • Mr. X • Height: 5’11’’ = 1.80m • Estimated Weight: 165lbs = 74.83kg • Stride: .748m per stride
Momentum: Beretta 92S • 2 shots • Muzzle velocity: 1250 ft/s = 381m/s • Mass: 970g = .97kg • Momentum = Mass X Velocity • M= .97 X 381 = 369.57
Momentum: Flintlock Pistol • 1 shot • Muzzle Velocity: 1000ft/s = 304.8m/s • Mass: 2.98lbs = 1.35kg • Momentum = Mass X Velocity • M= 1.35 X 304.8 = 411.99
Conservation of Momentum:Inelastic Collisions • (m1 + m2)V = (m1v1f) + (m2V2f) • (mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun
Conservation of Momentum: Inelastic Collisions • Finding the final velocity to use for projectile motion • Information for equation: • Mass of man/gun/bullet: 74.84kg • Mass of Bullets: .2kg each (3 bullets) • Mass of first gun (2 shots): .97kg • Mass of second gun (1 shot): 1.35kg • Velocity of Man running: 9.13m/s • Muzzle Velocity first gun: 381m/s • Muzzle Velocity of second gun: 304.8m/s
Conservation of Momentum: Inelastic Collisions: Equation (m1 + m2)V = (m1v1f) + (m2V2f)(mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun • First Shot • (74.84 + .2 + .2 + .2 + 2.32)9.13 = .2(381) + (74.84 + 2.32)vf • 709.95 = 76.2 + 77.16vf • Vf = 8.21m/s • Second Shot • (74.84 + .2 + .2 + 2.32)8.21 = .2(381) = (74.84 + 2.32)vf • 636.77 = 76.2 + 77.16vf • 560.57 = 77.16vf • Vf = 7.27 m/s • Third Shot • (74.84 + .2 + 2.32)7.27 = .2(304.8) + (74.84 + 2.32)vf • 562.41 = 60.96 + 77.16vf • 501.45 = 77.16vf • Vf = 6.50m/s
Projectiles: Time it should take to jump the distance • d = vxt because horizontal velocity is constant • City of Chicago street measurements: • D = 100 ft = 30.48m • 30.48m = 9.13m/s x time • t = 3.34s
Projectiles: How much height he would lose in that time • H = ½ g t2 • H = ½ 9.81 m/s2(3.34 sec)2 • H = 55.78m • 15 times that shown in the video